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Mathematics 24 Online
getabaggniy:

(Plz Help due today plz help me boost my grade up) A proportional relationship between the number of pounds of potatoes (x) and the price in dollars (y) is graphed, and the ordered pair (5, 4) is on the graphed line. Part A: What is the price of 1 pound of potatoes? Show your work. (8 points) Part B: What does the ordered pair (10, 8) on the graph represent? Explain in words. (2 points)

XioGonz:

@darkknight

darkknight:

Is there a graph that u need to post associated with the problem?

YNWMelly:

was that a direct answer?

darkknight:

u plagarized that

YNWMelly:

yes but i put the person's name at the bottom and is was from questioncove

darkknight:

Anyways, I can help you, just bear with me

getabaggniy:

It dont even show a graph so thats why im confused

YNWMelly:

its 4 dollars for 5 pounds. divide 5 by 5 and you get one pound. do the same thing with the other side and divide 4 by 5. you get .8 dollars (80cents) is how much 1 pund of potatoes cost

YNWMelly:

would that be right @darkknight ?

darkknight:

This is a proportional relationship. so it is linear with a y-intercept of 0.. So the slope is 5/4, comparing the pounds to potatoes So basically the equation is y=5/4x Now to find the price of 1 pound, we plug in 1 for x So y = (5/4)(1) where y is the price, so what is y? Part 2: The ordered pair (10,8), think about what this means, x is the pounds and y is the cost So for ___ pounds of potatoes, it costs ____ dollars...

darkknight:

No melly, you are incorrect

YNWMelly:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @darkknight No melly, you are incorrect \(\color{#0cbb34}{\text{End of Quote}}\) for the first one? and i was guessing on the second

darkknight:

Wait a mnute... disregard what I said before for the first one. Basically its 5 pounds to 4 dollars, So divide 5 by 5 (to find price for one pound) and 4 by 5 (to find price for one pound, we just divided both sides of the eqn by 4)

darkknight:

So YNw melly u were correct for the first one

YNWMelly:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @darkknight So YNw melly u were correct for the first one \(\color{#0cbb34}{\text{End of Quote}}\) ok thank you!

getabaggniy:

Thank you guys really appreciate it :)

darkknight:

np

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