Question

screenshot below

Answer 1

Explicit Formula:
\[a(n)=3+2(n-1)\]

Answer 2

@jhonyy9

Answer 3

So,
\(1|2|3\)
\(2|8|32\)

\[f(n)=2\times(3)^n-1\]

Answer 4

Jhonny? Correct?

Answer 5

so the numbers from the top lines are the roots of the functions from the bottom lines

just you need substitute them in place of x inside every function and in this way will get the right answers easy

Answer 6

Is the first one I gave correct?

Answer 7

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Imagine
So,
\(1|2|3\)
\(2|8|32\)

\[f(n)=2\times(3)^n-1\]
\(\color{#0cbb34}{\text{End of Quote}}\)

Answer 8

oh dang i cant help u with this sorry only in 7th grade XD

Answer 9

\(\color{#0cbb34}{\text{Originally Posted by}}\) @fireballfireball
oh dang i cant help u with this sorry only in 7th grade XD
\(\color{#0cbb34}{\text{End of Quote}}\)
its fine

Answer 10

for n= 1 what you get ?

Answer 11

n=1-1=0
2x3=6
2+6=8.

Answer 12

yall lost me

Answer 13

Nerd math talk here.

Answer 14

no

n is there exponent

Answer 15

Yeah, but when subtracted by 1, it becomes 0.

Answer 16

O wait.

Answer 17

no

Answer 18

\[3^0=1\]
\[2\times1=2\]
|\(1\)|
|\(2\)|

Answer 19

Ah that makes more sense.

Answer 20

I have to pay more attention.

Answer 21

no

what is the function

Answer 22

\[f(n)=2\times(3)^n-1\]

Answer 23

The -1 is a also exponent. but it wouldn't let me place it.

Answer 24

3^(1) = 3

Answer 25

No... Jhonny,

Answer 26

That is the function.

Answer 27

but sure 3 on power of 1 equal 3

Answer 28

You have to subtract The exponet "1" from -1 to get you exponet 0.

Answer 29

Then 3^0=1.

Answer 30

Then, 2x1=2.

Answer 31

f(1) = 2*3^1 -1 = 6 -1 = 5

Answer 32

No Jhonny.

Answer 33

so would 1 2 3
3 6 12
would that be f(n)=2 x (6) ^ n-1?

Answer 34

yes but how you wrote the 1 not is exponent

Answer 35

oh sorry

Answer 36

One is the exponent.

Answer 37

f(n) = 2*3^(n-1)

Answer 38

Correct.

Answer 39

this is the function

Answer 40

1|2|3
2|8|32

Answer 41

so would 1 2 3
2 12 72 be
f(n)=3 x (4) ^ n-1?

Answer 42

f(n) = 2*3^(1-1)
2x3^0
3^0=1
2x1=2

Answer 43

sorry in case of the first for n=2

not is right

Answer 44

so i was incorrect?

Answer 45

for the first for n=2 f(2) = 6 not 8

Answer 46

im confused now

Answer 47

why ?

f(2) = 2*3^(2-1) = 2*3^1 = 6

Answer 48

math just confuses the crap out of me, never understood and barely passed since like 5th grade, but I'm slowly starting to understand it more

Answer 49

@Imagine

Answer 50

jhonyy @imagine wrote the equation wrong
she meant to write \[2 \times (3)^{n-1}\] if that handles the confusion

Answer 51

Now easiest way to solve this is to plug in values for 1 2 and 3 for n. And whatever table the output matches that is the explicit formula for that one. For example is u plug in 1, 2 and 3, into one of the explicit formulas, and end up with f(n) = 2, 8 and 32 then that explicit formula is what is used for that specific table