Simplify.....
help??
how tho-
I wanna know how..
The answer that Mathway.com offered me isn't one of your answer choices, I can't place it here.
I'll try in another place with the steps
ok
\[\sqrt[20]{3}\] i only get this
\(\color{#0cbb34}{\text{Originally Posted by}}\) @mathclass \[\sqrt[20]{3}\] i only get this \(\color{#0cbb34}{\text{End of Quote}}\) no direct answers
but it is no the answer
not*
3 to the root 4 = 3^(1/4) likewise 3 to the root 5 = 3^(1/5)
I still dont understand o-o
nvm I get it now
\[\sqrt[4]{3}=3^{1/4}\]
3 1/4 over 3 1/5
what do u think from here?
subtract the fractions.. I think
1/4 - 1/5 = 5/20 - 4/20
=1/20 lol i dipped I was in class yes u got it correct.
tysm
Yes whenever u have something like that you subtract fractions, when its like this \[3^5)(3^6)\] you can add to 3^11
np
\(\color{#0cbb34}{\text{Originally Posted by}}\) @darkknight Yes whenever u have something like that you subtract fractions, when its like this \[3^5)(3^6)\] you can add to 3^11 \(\color{#0cbb34}{\text{End of Quote}}\) ok thx
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