Question

2Al + Fe2o3 -> 2Fe + Al2o3

What is oxidized, reduced, and unchanged?

Answer 1

Just need a bit of help for my last assignment....

Answer 2

nvm I think I got it... the o3 is unchanged, Al is oxidized and Fe is reduced. I'm not 100% sure though.

Answer 3

\(\color{#0cbb34}{\text{Originally Posted by}}\) @ramen
nvm I think I got it... the o3 is unchanged, Al is oxidized and Fe is reduced. I'm not 100% sure though.
\(\color{#0cbb34}{\text{End of Quote}}\)
Oxidation is loss of electrons. Reduction is gain of electrons. So that's correct

Answer 4

Yup, I was just tentative on which elements were in those categories.

Answer 5

\(\color{#0cbb34}{\text{Originally Posted by}}\) @ashyboy007
\(\color{#0cbb34}{\text{Originally Posted by}}\) @ramen
nvm I think I got it... the o3 is unchanged, Al is oxidized and Fe is reduced. I'm not 100% sure though.
\(\color{#0cbb34}{\text{End of Quote}}\)
Oxidation is loss of electrons. Reduction is gain of electrons. So that's correct
\(\color{#0cbb34}{\text{End of Quote}}\)

Yep that's right.

Oxidation is a method in which electrons are lost and thus the element's oxidation number rises. Reduction is when electrons are obtained and thus the element's oxidation number reduces.

Answer 6

Oxidant is Ag. Reductant is Fe.

Answer 7

\(\color{#0cbb34}{\text{Originally Posted by}}\) @justus
Oxidant is Ag. Reductant is Fe.
\(\color{#0cbb34}{\text{End of Quote}}\)
Nvm.. it's right

Answer 8

One second

Answer 9

I think the oxidizing agent is Fe2O3 and reducing is Al because Fe2O3 is reduced to Fe on the other hand Al is oxidized to Al2O3.

Answer 10

@ramen

Answer 11

Yea, it's right bcs O was added in Al and Fe lost O

Answer 12

So is anything unchanged?

Answer 13

I don't believe so.

Answer 14

Ok thanks for your help guys

Answer 15

\(\color{#0cbb34}{\text{Originally Posted by}}\) @ramen
Ok thanks for your help guys
\(\color{#0cbb34}{\text{End of Quote}}\)
Yw!

Answer 16

\(\color{#0cbb34}{\text{Originally Posted by}}\) @ramen
Ok thanks for your help guys
\(\color{#0cbb34}{\text{End of Quote}}\)
NP