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Mathematics 21 Online
hhanan:

...

hhanan:

dontsaymyname:

Does it have to be exact or decimal?

hhanan:

I don't know that's all the problem

dontsaymyname:

\[\sqrt[3]{9}^5\] would be the 1st one

supie:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @dontsaymyname \[\sqrt[3]{9}^5\] would be the 1st one \(\color{#0cbb34}{\text{End of Quote}}\) More details please? Why is this the answer?

dontsaymyname:

Uhm idk, Mathway.com lol

hhanan:

so that is in radical form?

dontsaymyname:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @hhanan so that is in radical form? \(\color{#0cbb34}{\text{End of Quote}}\) I believe so

supie:

Ok so the way you do it is you take the number that ins't the exponent but we take 9, pu Wizard inside the radical so it becomes \(\sqrt{9}\) we take the denominator then put it before the radical \[\sqrt[3]{9}\] then with the numerator you keep it an exponent so it would look like this \(\sqrt[3]{9}^5\)

supie:

so @dontsaymyname you are correct just explain how you got your answer next time.

dontsaymyname:

Thank you, Supie :>

supie:

So just follow that same thing for the next one then you'll get your answer @hhanan

supie:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @dontsaymyname Thank you, Supie :> \(\color{#0cbb34}{\text{End of Quote}}\) np ty

hhanan:

57/2?

dontsaymyname:

the 2nd one is \[\sqrt{25^7}\]

dontsaymyname:

Uhmm and just use the same reasoning as Supie explained

hhanan:

ok ty

dontsaymyname:

np :)

jhonyy9:

so this is in this way bc, the denominator of fractional exponent always is the index of the radical

jhonyy9:

@Laylalyssa

jhonyy9:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9 so this is in this way bc, the denominator of fractional exponent always is the index of the radical \(\color{#0cbb34}{\text{End of Quote}}\) this is the rule in case of a fractional exponent

Laylalyssa:

I thought they already answered it

jhonyy9:

to re-write it in the form of radical

jhonyy9:

yes i know but without any clearly explication

Laylalyssa:

oh ok

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