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Does it have to be exact or decimal?
I don't know that's all the problem
\[\sqrt[3]{9}^5\] would be the 1st one
\(\color{#0cbb34}{\text{Originally Posted by}}\) @dontsaymyname \[\sqrt[3]{9}^5\] would be the 1st one \(\color{#0cbb34}{\text{End of Quote}}\) More details please? Why is this the answer?
so that is in radical form?
\(\color{#0cbb34}{\text{Originally Posted by}}\) @hhanan so that is in radical form? \(\color{#0cbb34}{\text{End of Quote}}\) I believe so
Ok so the way you do it is you take the number that ins't the exponent but we take 9, pu Wizard inside the radical so it becomes \(\sqrt{9}\) we take the denominator then put it before the radical \[\sqrt[3]{9}\] then with the numerator you keep it an exponent so it would look like this \(\sqrt[3]{9}^5\)
so @dontsaymyname you are correct just explain how you got your answer next time.
Thank you, Supie :>
So just follow that same thing for the next one then you'll get your answer @hhanan
\(\color{#0cbb34}{\text{Originally Posted by}}\) @dontsaymyname Thank you, Supie :> \(\color{#0cbb34}{\text{End of Quote}}\) np ty
57/2?
the 2nd one is \[\sqrt{25^7}\]
Uhmm and just use the same reasoning as Supie explained
ok ty
np :)
so this is in this way bc, the denominator of fractional exponent always is the index of the radical
@Laylalyssa
\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9 so this is in this way bc, the denominator of fractional exponent always is the index of the radical \(\color{#0cbb34}{\text{End of Quote}}\) this is the rule in case of a fractional exponent
I thought they already answered it
to re-write it in the form of radical
yes i know but without any clearly explication
oh ok
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