Question

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Answer 1

its said divide so divide it

Answer 2

\(\color{#0cbb34}{\text{Originally Posted by}}\) @LjTheBaller16
its said divide so divide it
\(\color{#0cbb34}{\text{End of Quote}}\)
that does not help

Answer 3

okay

Answer 4

For the problem, i got \[5x^4y^5z^{36}\]

Answer 5

@jhonyy9 could you help me

Answer 6

you need to divide the top first and the the bottom and then just divide.
sorry if htis doesnt help

Answer 7

\(\color{#0cbb34}{\text{Originally Posted by}}\) @hhanan
For the problem, i got \[5x^4y^5z^{36}\]
\(\color{#0cbb34}{\text{End of Quote}}\)

Answer 8

\(\color{#0cbb34}{\text{Originally Posted by}}\) @hhanan
For the problem, i got \[5x^4y^5z^{36}\]
\(\color{#0cbb34}{\text{End of Quote}}\)
Not quite

Answer 9

You should set it up like this:
\[\frac{ 20xy^4z^12 }{ 4x^3yz^24 }\]

Answer 10

i got \[\frac{ 5y^3 }{ x^2z^{12} }\]

Answer 11

I think its \[5y^3/x^2y^12\]

Answer 12

\[\frac{ 20x y^{4}z^{12} }{ 4x^{3}y z^{24} } = \frac{ 5*4xy y^{3}z^{12} }{ 4x x^{2}y z^{12}z^{12} }\]

look please on this and try simplifie top and bottom (in numerator and denominator) what you can - and so what you will get ...

Answer 13

\(\color{#0cbb34}{\text{Originally Posted by}}\) @hhanan
i got \[\frac{ 5y^3 }{ x^2z^{12} }\]
\(\color{#0cbb34}{\text{End of Quote}}\)

Answer 14

\(\color{#0cbb34}{\text{Originally Posted by}}\) @mw104969
I think its \[5y^3/x^2y^12\]
\(\color{#0cbb34}{\text{End of Quote}}\)
y in denominator will be simplified

Answer 15

\(\color{#0cbb34}{\text{Originally Posted by}}\) @hhanan
\(\color{#0cbb34}{\text{Originally Posted by}}\) @hhanan
i got \[\frac{ 5y^3 }{ x^2z^{12} }\]
\(\color{#0cbb34}{\text{End of Quote}}\)
\(\color{#0cbb34}{\text{End of Quote}}\)
This is correct

Answer 16

\(\color{#0cbb34}{\text{Originally Posted by}}\) @hhanan
\(\color{#0cbb34}{\text{Originally Posted by}}\) @hhanan
i got \[\frac{ 5y^3 }{ x^2z^{12} }\]
\(\color{#0cbb34}{\text{End of Quote}}\)
\(\color{#0cbb34}{\text{End of Quote}}\)
yes correct

Answer 17

thank you both

Answer 18

np
anytime
yw