Question

An examination consists of three parts. In part A, a student must answer 2 of 3 questions. In part B, a student must answer 6 of 8 questions and in part C, a student must answer all questions. How many choices of questions does the student have?

Answer 1

non nom non

Answer 2

\(\color{#0cbb34}{\text{Originally Posted by}}\) @DanGonz
non nom non
\(\color{#0cbb34}{\text{End of Quote}}\)
wat?

Answer 3

the student has 4 choices

Answer 4

ANYWAYS........

Answer 5

\(\color{#0cbb34}{\text{Originally Posted by}}\) @DanGonz
ANYWAYS........
\(\color{#0cbb34}{\text{End of Quote}}\)
how is it 4

Answer 6

hehe um iont know

Answer 7

i guess

Answer 8

\(\color{#0cbb34}{\text{Originally Posted by}}\) @DanGonz
hehe um iont know
\(\color{#0cbb34}{\text{End of Quote}}\)
oh u want me to fail

Answer 9

i never said that

Answer 10

im tryin to be funny

Answer 11

well it dont work bye

Answer 12

\(\color{#0cbb34}{\text{Originally Posted by}}\) @DanGonz
im tryin to be funny
\(\color{#0cbb34}{\text{End of Quote}}\)
ik

Answer 13

:(

Answer 14

I just don't want to get it wrong

Answer 15

Given: x2 - 3|x - 2| - 4x = - 6

Let Y = x - 2

which gives x = Y + 2

Substitute in the equation above: (Y + 2)2 - 3|Y| - 4(Y + 2) = - 6

Y2 - 3|Y| + 2 = 0

Notice: Y2 = |Y|2

Rewrite the equation as: |Y|2 - 3|Y| + 2 = 0

(|Y| - 2)(|Y| - 1) = 0

Solve for |Y|: |Y| = 2 , |Y| = 1

Solve for Y: Y = 2, -2 , 1 , -1

solve for x using x = Y + 2.

So: x = 4 , 0 , 3 , 1