Write the first four terms of a geometric sequence. Using the values you have written, calculate the common ratio and write the rule for the nth term. Show all calculations.
@supie
@darkknight
\(\color{#0cbb34}{\text{Originally Posted by}}\) @JammarWalker @darkknight \(\color{#0cbb34}{\text{End of Quote}}\) lol
alr well i can take this, lets make up a random geometric sequence \[An = a * r ^{n-1}\] followed by this formula
working backwards might be easier, lets assign r = 3 and a = 5 Now find the first 4 terms of the sequence, plug in n = 1 then 2 then 3 then 4
basically cheating the system, it askes u to calculate the common ratio and stuff and the eqn but we defined that ahead of time, so you can easily solve parts 2 and 3
just find the first 4 terms of the sequence, plug in n = 1 then 2 then 3 then 4
48828125
?
u should have 4 values, one for the 1st term, 1 for the second... 1 for the fourth
3,5,8
not quite... \[An = 5 * 3^{(n-1)}\] plug in 1, 2 3 and 4 for n
3a
plug in 1 for a first, what do you get for the variable (An)???
a
sorry for n, what am i saying lmao
plug in 1 for n,
good job @darkknight - congrats !
so put a1
\[Y = 5*3^{(n-1)}\] please plug in 1 for n and see what Y equals
5
now plug in 2
15
keep going, plug in 3 and 4
45,135
yep now ur done
amd thank you @jhonyy9
so i put all of that in for the problem
mhm
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