Triangle XYZ was dilated by a scale factor of 2 to create triangle ACB and sin ∠X = 5 over 5 and 59 hundredths. Part A: Use complete sentences to explain the special relationship between the trigonometric ratios of triangles XYZ and ABC. You must show all work and calculations to receive full credit. Part B: Explain how to find the measures of segments CB and AB. You must show all work and calculations to receive full credit.
ok so like a first step how you think what mean a dilation by a scale factor of 2 ? for example a length of 1 unit how many will be ?
@supie
What exactly do you mean? Are asking what I think a dilation of two is?
yes ofc
Well a dilation is when the triangle is made bigger by a number/ratio, in this case 2, as long as you dilate by the same number all the triangles are proportionate.
ok but i ve asked you a little simple question what mean a dilation by two ? with this example pls.
@Laylalyssa why is this so difficile to answer ?
\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9 @Laylalyssa why is this so difficile to answer ? \(\color{#0cbb34}{\text{End of Quote}}\) difficult*
Well the scale factor of 2 was used to dilate triangle XYZ into triangle ACB?
Well I guess he gave up, does anyone know how to do this?
@jhonyy9 are u gonna finish☔️
So lets explain the special relationship between the trig ratios of XYZ and ABC, if you know what a ratio is, we can do this pretty easy. A dilation just means increasing (or decreasing) all sides by the same scale factor, when we do this we can find a ratio between corresponding side lengths on both triangles, For example If I have a triangle here |dw:1614184723189:dw|(assume both triangles are similar, and the bigger triangle is dilated by a factor of 2, meaning all sides are twice as big,) we can set a ratio comparing the small triangle to the big one, which would be 1:2 in the case we just discussed. (btw this is all background not answering the question just yet). Since in your problem we are dilating by a scale factor of 2 we can find the trig ratios of both triangles
Now getting into the meat of this, "Triangle XYZ was dilated by a scale factor of 2 to create triangle ACB and sin ∠X = 5 over 5 and 59 hundredths." we need to explain the trig ratios between the 2 triangles we are given "sin ∠X = 5 over 5 and 59 hundredths"
Lets start out by drawing an angle x, this angle will be opposite the side length of 5 and the hypotenuse will be 5.59 Tthis is because sin is \[opposite/hypotenuse\] |dw:1614185055319:dw|
It does provide an image, but I'm not sure how to make it into a file.
now that was for triangle XYZ, so side X = 5 (because the side is named opposite of the angle,) also the image doesnt really matter its fine because you just need to visualize it.
Actually for your image is y the hypotenuse or z???
Y is the right angle so I would suppose z is the hypotenuse.
|dw:1614185284168:dw|this is the drawing then, that we will refer too
Ok, so really the next thing we want to do is find the side length z, can you do taht?
Probably not
ugh I was being dumb, it does not specifiy if this was a right triangle. Is it?
Sorry its only in anything math related that I'm completely useless
no no no, ur doing fine. In the drawing is the triangle a right triangle?
No, its not a right trangle.
smh ok now the approach to that is the triangle i gave you before, just imagine its like a bit off or something (not a right triangle). So from here we need to use law of cosine. Do you know this?
I don't think I've ever heard of it.
Ok yeah I'm hopeless, thank you for staying patient with me.
hmm, this is super confusing if you havent heard of the rule, also super weird because if this triangle isnt a right triangle then we cant use pythagorean theorem, at this point seeing the picture might help. Click the attach file button right below
But it isn't a file, and I dont know how to make it into one.
you can screen shot it., crop out whatever you need to crop out and then attach as a file
Is there another to screenshot other than clicking prt sc?
not sure what ur talking about... you should be able to screenshot, save the SS (which might automatically do) then click the button and upload the SS
The problem is, I don't know how to screenshot
As I was saying, completely hopeless.
I even managed to lose my headphones, and I had just found them yesterday *face palm*
asdfghjkl, search it up on google, type in how to SS on *insert device name here*
Hey I got it!
alr, hold on 10-15 min
Yes, sorry for taking so much of your time already.
oh breh that actually is a right triangle XD
ok, we dont gotta go into the law of cosine junk xD, for an fyi, if a triangle has a box, it means it is a right triangle, as u can see in that pic
\(\color{#0cbb34}{\text{Originally Posted by}}\) @darkknight Ok, so really the next thing we want to do is find the side length z, can you do taht? \(\color{#0cbb34}{\text{End of Quote}}\) pythagorean theroem \[x^2+z^2=y^2\] (y is hypotenuse) \[5^2+z^2=5.59^2\] solve for z
Oh...woops
*facepalm* lol ur good, can u find z?
I..dont think so
\[z^2=5.59^2-5^2\] \[z=\sqrt{5.59^2+5^2}\] solve for z?
7.49 rounded to 7.5?
SMH SMH SMH I meant \[z = \sqrt{5.59^2-5^2}\] very sorry
Oh thats fine
2.5 then?
umm if u did the math right it should be right, now the rest is pretty easy we need to find the trig ratios Lets say sinx = 5/5.59 guess what? sin(a) also equals 5/5.59 !!! This is because we dilated, sin is a ratio, since the ratio of the 2 triangles are the same, for corresponding angles the sin ratio, the cos ratio, tan ratio, etc. will be the same for angle X and angle A, likewise for the other angles. Tis is part 1 so use like another example maybe with respect to another variable like z and b. On the smaller triangle we found every side length, since the bigger triangle is just twice that we can solve part 2 but just multiplying the corresponding side on the smaller triangle by 2
Sorry I'm just trying to figure out what to write exactly.
Ok so would the answer There is a relationship between the triangles because of the dilation of 2 z=square root 5.59squared−5squared z=square root (559/100)squared-25 z=2.49 Round up and you get 2.5 sinx=5/5.59 and sin(a) is also 5/5.59 This is because we dilated, sin is a ratio, since the ratio of the 2 triangles are the same, for corresponding angles the sin ratio, the cos ratio, tan ratio, etc. will be the same for angle X and angle A, likewise for the other angles. If you find the side lengths for triangle XYZ you are able to know the side lengths of ACB by multiplying them by 2 since it was dilated by a scale factor of 2.
For part A
im back, hold on a moment
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Seafoam Ok so would the answer There is a relationship between the triangles because of the dilation of 2 z=square root 5.59squared−5squared z=square root (559/100)squared-25 z=2.49 Round up and you get 2.5 sinx=5/5.59 and sin(a) is also 5/5.59 This is because we dilated, sin is a ratio, since the ratio of the 2 triangles are the same, for corresponding angles the sin ratio, the cos ratio, tan ratio, etc. will be the same for angle X and angle A, likewise for the other angles. If you find the side lengths for triangle XYZ you are able to know the side lengths of ACB by multiplying them by 2 since it was dilated by a scale factor of 2. \(\color{#0cbb34}{\text{End of Quote}}\) exactly this, part 1 done, but now for part 2 "Part B: Explain how to find the measures of segments CB and AB. You must show all work and calculations to receive full credit. " you have to actually find CB and AB, can u do that now?
I don't think so.
CB is just side x times 2... you are already given side x's length, multiply by 2 to get CB for AB take its corresponding side and multiply by 2
I see the concept, but what are the side lengths for the triangle?
Sorry I left for so long, I had to complete my DBA
look at the earlier drawings, we wrote out x and y and solved for z. everything is given already
Ok so z is 2.5 but where was x and y said?
And is z really a side length? It looks like its written at the angle.
\(\color{#0cbb34}{\text{Originally Posted by}}\) @darkknight Created with Raphaël 2.0.2Reply Using Drawingthis is the drawing then, that we will refer too \(\color{#0cbb34}{\text{End of Quote}}\) @seafoam the lowercase are the angles, and the sides opposite it are sides X, Y, Z are sides. x, y, z are angles
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