Determine the intercepts of the line. y=-3x+12y=
ignore the last equal sign
y = -3x + 12 To find the x-intercept, you plug in y = 0 and solve for x To find the y-intercept, you plug in x = 0 and solve for y
So let's find the x-intercept first y = -3x + 12 Plug in y = 0 and we'll get 0 = -3x + 12 can you solve for x?
no i dont know how to solve this
we want to get x all by itself so we have 0 = -3x + 12 Let's take 12 to the other side What happens when you subtract 12 on both sides?
judging from your silence, mhmm let's break it down even further what is 0 - 12= ?
okay so 0 = -3x + 12 subtracting 12 on both sides 0 - 12 = -3x + 12 - 12 now 12 on the right side of the equation gets cancelled out and we're left with -12 = -3x What is -12/3 = ?
nono negative 4
oops, you're right but I forgot the negative so what is -12/-3 = ?
ok so 4
yes so we get -12 = -3x divide -3 on both sides and we'll get -12/-3 = -3x/-3 4 = x so our x-intercept is 4
Does that make sense?
For whenever you come back online- To find the y-intercept, just plug in x=0 y = -3x + 12 y = -3(0) + 12 What is -3 * 0 = ? And then add 12 And that's your y-intercept
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