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Mathematics killer:

Solve the inequality. Graph the solution. 3p+2≥−10 The solution is jhonyy9:

like a first step subtract from both sides 2 so what will get ? jhonyy9:

@supie any idea ? supie:

So when i subtract 2 from both sides i got $$3p≥−12$$ because $$3p+2−2≥−10−2$$ -10-2=12 so $$3p≥−12$$ then divide both sides by 3 ??? jhonyy9:

$$\color{#0cbb34}{\text{Originally Posted by}}$$ @supie So when i subtract 2 from both sides i got $$3p≥−12$$ because $$3p+2−2≥−10−2$$ -10-2=12 so $$3p≥−12$$ then divide both sides by 3 ??? $$\color{#0cbb34}{\text{End of Quote}}$$ good idea jhonyy9:

continue pls. jhonyy9:

@killer ok ? supie:

Ok so $$\LARGE\frac{3p}{3}≥\frac{-12}{3}$$ $$\cancel{\frac{3p}{p}}≥\frac{-12}{3}$$ (3p/p cancels) so all that is lef tis $$\frac{-12}{3}$$ so that needs to be simplified $$\frac{-12}{3}=?$$ $$p≥?$$ supie:

left is * ._. jhonyy9:

$$\color{#0cbb34}{\text{Originally Posted by}}$$ @supie Ok so $$\LARGE\frac{3p}{3}≥\frac{-12}{3}$$ $$\cancel{\frac{3p}{p}}≥\frac{-12}{3}$$ (3p/p cancels) so all that is lef tis $$\frac{-12}{3}$$ so that needs to be simplified $$\frac{-12}{3}=?$$ $$p≥?$$ $$\color{#0cbb34}{\text{End of Quote}}$$ attention pls on the left side 3 cancel by 3 not p by p jhonyy9:

3p/3 not 3p/p supie:

Oh that's what I meant. jhonyy9:

$$\color{#0cbb34}{\text{Originally Posted by}}$$ @jhonyy9 $$\color{#0cbb34}{\text{Originally Posted by}}$$ @supie Ok so $$\LARGE\frac{3p}{3}≥\frac{-12}{3}$$ $$\cancel{\frac{3p}{p}}≥\frac{-12}{3}$$ (3p/p cancels) so all that is lef tis $$\frac{-12}{3}$$ so that needs to be simplified $$\frac{-12}{3}=?$$ $$p≥?$$ $$\color{#0cbb34}{\text{End of Quote}}$$ attention pls on the left side 3 cancel by 3 not p by p $$\color{#0cbb34}{\text{End of Quote}}$$ on the left side first you ve wrote 3p/3 but you continue with 3p/p jhonyy9:

@supie supie:

Yes i know. I meant $$\frac{3p}{3}$$ but I accidently did $$\frac{3p}{p}$$ jhonyy9:

$$\color{#0cbb34}{\text{Originally Posted by}}$$ @jhonyy9 $$\color{#0cbb34}{\text{Originally Posted by}}$$ @jhonyy9 $$\color{#0cbb34}{\text{Originally Posted by}}$$ @supie Ok so $$\LARGE\frac{3p}{3}≥\frac{-12}{3}$$ $$\cancel{\frac{3p}{p}}≥\frac{-12}{3}$$ (3p/p cancels) so all that is lef tis $$\frac{-12}{3}$$ so that needs to be simplified $$\frac{-12}{3}=?$$ $$p≥?$$ $$\color{#0cbb34}{\text{End of Quote}}$$ attention pls on the left side 3 cancel by 3 not p by p $$\color{#0cbb34}{\text{End of Quote}}$$ on the left side first you ve wrote 3p/3 but you continue with 3p/p $$\color{#0cbb34}{\text{End of Quote}}$$ @killer did you get the answer now ? jhonyy9:

questions ? jhonyy9:

@supie how you graph the solution ?

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