Question

A ball is launched from 8 feet off the ground at an initial vertical speed of 64 feet per second. It is aimed across a field at a target also 8 feet off the ground. The height of the ball at a time, t, in seconds, is given by the function, h = –16t 2 + 64t + 8. It will take the ball
seconds to hit its target.

Answer 1

@supie do you understand this problem ? i think there is anything missed ...

Answer 2

@Convert your opinion pls. ?

Answer 3

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9
@Convert your opinion pls. ?
\(\color{#0cbb34}{\text{End of Quote}}\)
did you get make sens ?

Answer 4

h = –16t 2 + 64t + 8 represents the general formula of motion which goes by: h(t) = h0 + v0t - 16t² . In which h0 is the initial height (8 feet), v0 is the initial velocity (64 feet per second), and t is the time in seconds. To determine, for example the maximum height, you would plug in the time to the equation. You would do the same for seconds.
What would you think the answer would be if we're trying to find the seconds the ball takes to hit the target?

Answer 5

ok i understand but we need to know the distance till the target not the height how is given
is given the height of the ball at start and the height of the target and we know that the ball go vertical
how can you find the time in what the ball hit the target without to know the distance between the place from where start the ball and till the target ?

Answer 6

or i think i missed anything ???

Answer 7

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9
ok i understand but we need to know the distance till the target not the height how is given
is given the height of the ball at start and the height of the target and we know that the ball go vertical
how can you find the time in what the ball hit the target without to know the distance between the place from where start the ball and till the target ?
\(\color{#0cbb34}{\text{End of Quote}}\)
Oh yes, I believe that is true @b1az3 could you give us the length of the field?

Answer 8

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Convert
\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9
ok i understand but we need to know the distance till the target not the height how is given
is given the height of the ball at start and the height of the target and we know that the ball go vertical
how can you find the time in what the ball hit the target without to know the distance between the place from where start the ball and till the target ?
\(\color{#0cbb34}{\text{End of Quote}}\)
Oh yes, I believe that is true @b1az3 could you give us the length of the field?
\(\color{#0cbb34}{\text{End of Quote}}\)
ty so much you understood it me now

Answer 9

ty that you helped me clarifie this

Answer 10

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Convert
\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9
ok i understand but we need to know the distance till the target not the height how is given
is given the height of the ball at start and the height of the target and we know that the ball go vertical
how can you find the time in what the ball hit the target without to know the distance between the place from where start the ball and till the target ?
\(\color{#0cbb34}{\text{End of Quote}}\)
Oh yes, I believe that is true @b1az3 could you give us the length of the field?
\(\color{#0cbb34}{\text{End of Quote}}\)
ty so much you understood it me now
\(\color{#0cbb34}{\text{End of Quote}}\)
Yeah, sorry at 1st I was confused by it and thought the 64 feet was the distance my bad

Answer 11

64 feet ? how from where ?

Answer 12

ohh this is the speed

Answer 13

ok

np


ty so much you helped clarifie it