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Mathematics 20 Online
ENHZ:

Two families go to a hockey game. One family purchases two adult tickets and four youth tickets for $28. Another family purchases four adult tickets and five youth tickets for $45.50. Let x represent the cost in dollars of one adult ticket and let y represent the cost in dollars of one youth ticket. Write and solve a linear system of equations to find the cost of one adult and one youth ticket.

AZ:

Hey there! Welcome to QuestionCove! Do you have any idea how to come up with the equations we will eventually solve?

ENHZ:

Hi, I only needed to put this up here to see if I could get the equation itself.

ENHZ:

Probably asking for too much :/

AZ:

Sure! Not at all!

AZ:

We have two families One family purchases 2 adult tickets and 4 youth tickets for $28 The other family purchases 4 adult tickets and 5 youth tickets for $45.50 x is the cost of 1 adult ticket y is the cost of 1 youth ticket

AZ:

(That's basically the question just made easier to read to separate all the information haha)

ENHZ:

Okay! Anything that helps is great! Thank you!

AZ:

Let's focus on the first family So we said that `x` is how much 1 adult ticket costs If the first family bought 2 adult tickets, how much would that cost? As an example: I say that one watermelon costs 5 dollars and I buy 4 of them then how much did 4 watermelons cost? It's a simple multiplication 5*4 = 20 So here we have an `x` x is just our variable, it's a number that we're trying to eventually solve for so how much would 2 adult tickets cost if each adult ticket costs `x` dollars?

ENHZ:

x*2?

AZ:

Exactly! Or 2x Now the same thing for the youth 1 youth ticket costs `y` dollars and the first family bought 4 of them how much do 4 youth tickets cost?

ENHZ:

4*y

ENHZ:

(x*2) + (4+y)??

AZ:

Exactly!

AZ:

x*2 is the same thing as 2x we write it like that because it saves space and is easier to read but it's the same thing- 2 times x or x times 2 same thing

ENHZ:

it seems smoother in my head when i do that, sorry

AZ:

so remember the first family bought 2 adult tickets and 4 youth tickets and all of those tickets costed 28 so 2x + 4y = 28

AZ:

No worries! I just wanted to make sure you understood that they were the same because when we write the equation it looks much cleaner to have 2x + 4y than to have (x*2) + (y*4)

ENHZ:

ok :)

ENHZ:

Adult=7, Child=3.5 i think

AZ:

no no, so we'll find a bunch of numbers that can work we can chose any random number for 'x' and find a price for y that would make it 28 the way to get the actual solution lies in the other equation!!

AZ:

Don't forget about the other family

ENHZ:

ohhhhhh

AZ:

So you know how we just made that first equation? Now we need to make a second equation and then we solve the equations together! The other family purchases 4 adult tickets and 5 youth tickets for $45.50

AZ:

Can you do it on your own this time? Or do you want me to help you with setting up the equation again

ENHZ:

x4 + y5

AZ:

good! And those 4 adult tickets + the 5 youth tickets costed a total of 45.50 ! so our second equation is 4x + 5y = 45.50 Does that make sense?

ENHZ:

yeah, let me plug it in

AZ:

so we have two equations that we need to solve 2x + 4y = 28 4x + 5y = 45.50 Do you know how to solve a system of equations? The substitution method? Elimination method?

ENHZ:

I learned them a while back, barely remember. It's fine, I think I can handle myself! THanks for the help!

AZ:

Of course! That's totally fine with me. If you get stuck, I'll still be here if you want me to help or check your answer!

ENHZ:

@AZ I got it right after a bit of trial and error! Thank you!

AZ:

Were you guessing numbers the whole time?! @ENHZ

AZ:

I could have shown you how to solve it so you wouldn't be guessing numbers because then it gets really difficult if the price of one of the tickets is 9.53 or something

ENHZ:

I just fell back on the $7 adult, $3.50 child, and ended up getting it right! @AZ

AZ:

That's correct! Do you know how to solve it by substitution or elimination method? Alternatively, you could have graphed both lines and saw where they intersected- that would be your answer

ENHZ:

I ended up using the substitution method

AZ:

Ah okay, good to hear! Also- this is a really good graphing calculator https://www.desmos.com/calculator/d0ni9dq6d9

ENHZ:

Thank you @AZ

AZ:

You're most welcome!

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