Question

What is the value of x in the following equation.

Answer 1

First on the left side

\(\Large (a^b)^c = a^{bc}\)

so multiply the exponents

what is 8 * 2x

Answer 2

And then on the right hand side

\(\Large \dfrac{a^{b}}{a^{c}} = a^{b-c}\)

what is

\(\Large \dfrac{3^{20x}}{a^{24}} = ?\)

just subtract the exponents

Answer 3

but one at a time, first answer what is

8 * 2x

Answer 4

16x

Answer 5

okay so now we have

\(\Large 3^{16x} = \dfrac{3^{20x}}{3^{24}}\)


so how can we simplify the right hand side

just take the exponents and subtract them so that way we can get rid of the fraction

Answer 6

0

Answer 7

let me give you colors again

\( \Large \dfrac{a^{\color{green}{b}}}{a^{\color{orange}{c}}} = a^{\color{green}{b}-\color{orange}{c}} \)

Answer 8

We already know the question....

Answer 9

Here's an example

\(\Large \dfrac{2^{12x}} {2^{8}} = 2^{(12x - 8)}\)

can you now do it for YOUR question?

Answer 10

\( \Large \dfrac{3^{20x}}{3^{24}} = ?\)

\(\color{#0cbb34}{\text{Originally Posted by}}\) @AZ
let me give you colors again

\( \Large \dfrac{a^{\color{green}{b}}}{a^{\color{orange}{c}}} = a^{\color{green}{b}-\color{orange}{c}} \)
\(\color{#0cbb34}{\text{End of Quote}}\)