Question

can someone help me

Answer 1

1. List the dimensions of your box. Be sure to include the units (in, cm, ft, etc.) length = 8in. width=5in. Height=1in.
2. Describe the shape of the cross section when the box is cut parallel to the base.
3. What is the surface area of the box?
4. What is the surface area of the box if it is scaled up by a factor of 10?
5. What is the volume of the box? 40in.
6. What is the volume of the box if it is scaled down by a factor of 1/10?

Answer 2

i only need help finding out numbers 2, 3, 4,6

Answer 3

For number two, here is what you want to do..
\[A=lw\]

\[A=8 \times 5\]

What is 8 times 5?

Answer 4

40

Answer 5

no

Answer 6

i already did 3

Answer 7

i need help with 2

Answer 8

so when u plug ur numbers in it will look like this

Surface Area = 2×(8×5 + 8×1 + 5×1)

work this out

Answer 9

\(\color{#0cbb34}{\text{Originally Posted by}}\) @HaydenwH
here is the formula you will use for 2


SA=2lw+2lh+2hw,
\(\color{#0cbb34}{\text{End of Quote}}\)
srry tht was 3 not 2

Answer 10

you can use this for number 2

https://www.learningfarm.com/web/practicePassThrough.cfm?TopicID=1402

Answer 11

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Astrid1
For number two, here is what you want to do..
\[A=lw\]

\[A=8 \times 5\]

What is 8 times 5?
\(\color{#0cbb34}{\text{End of Quote}}\)
you are finding surface area not area

Answer 12

Describe the shape of the cross section when the box is cut parallel to the base.

Answer 13

my shape was a rectangle

Answer 14

40 is not correct for the surface area too

Answer 15

\(\color{#0cbb34}{\text{Originally Posted by}}\) @skrtkobainn
my shape was a rectangle
\(\color{#0cbb34}{\text{End of Quote}}\)
did you click the link?

Answer 16

that would be cut parallel to the base

Answer 17

would it be a square if its cut in half

Answer 18

\(\color{#0cbb34}{\text{Originally Posted by}}\) @skrtkobainn
would it be a square if its cut in half
\(\color{#0cbb34}{\text{End of Quote}}\)
no in order for it to be a cube* all side would have to have the same measurements

Answer 19

i would say @Tranquility for questions 4 and 6