Question

Explain the difference between using the tangent ratio to solve for a missing angle in a right triangle versus using the cotangent ratio. You must use complete sentences and any evidence needed (such as an example) to prove your point of view.

Answer 1

hey

Answer 2

Tangent(x) = opposite/adjacent
Cotangent(x) = adjacent/opposite
do you know that?

Answer 3

no it dont say

Answer 4

Do you know any of the trigonometric ratios?

Answer 5

it dont give no number I think its just asking to explain how to do this

Answer 6

Mhmm.... they didn't teach anything before giving you hw-_-
The difference between tangent and cotangent is they're reciprocals. In tangent, it will be easier if you are solving for opposite, for cotangent, it will be easier if you are solving for the adjacent side.

Answer 7

Im doing virtual teachers not much help so I came here for help

Answer 8

Can I teach you all the trigonometric ratios please? lol
They are all necessary

Answer 9

yes Im confused

Answer 10

xD thx

Answer 11

So, the three main trigonometric ratios are
1. Sine.
2. Cosine.
3. Tangent
then, there are the reciprocals of them, aka 1/that
they are
1. Cosecant (reciprocal of sine)
2. Secant (reciprocal of cosine)
3. Cotangent (reciprocal of tangent)
There are also inverses, but that's not needed rn, well, tbh, i'm not too familiar with them lol.
But, remember those ^^^^

Answer 12

Then, there is Soh Cah Toa
Sin(x) = opposite/hypotenuse
Cos(x) = adjacent/hypotenuse
Tan(x) = opposite/adjacent

Answer 13

I almost forgot to ask, do you know which sides would be opposite, adjacent, and hypotenuse?

Answer 14

no

Answer 15

Okay.
Another question, are you in geometry or algebra 2

Answer 16

here is another problem i'm having issues with An observer (O) is located 900 feet from a building (B). The observer notices a helicopter (H) flying at a 49° angle of elevation from his line of sight. How high is the helicopter flying over the building? You must show all work and calculations to receive full credit. (10 points)

A right triangle is shown with one leg measuring 900 and another leg measuring h with an angle across from it measuring 49 degree

Answer 17

i-
i have to first tell you the basics of how to do it-_-
fundamental stuff now, questions later
can you answer my question?

Answer 18

geometry

Answer 19

okay, then for now, just remember that you use these ratios with only right angles
Got it?

Answer 20

yes

Answer 21

if this was the angle

Answer 22

h=hypotenuse
a=adjacent side
o=opposite side

Answer 23

If this was the angle

Answer 24

So, the opposite of the angle, is the opposite side, the hypotenuse is the longest leg, and the adjacent is the one next to the angle that is not the hypotenuse
Yea?

Answer 25

yea

Answer 26

Okay, so now we bring back
\(\color{#0cbb34}{\text{Originally Posted by}}\) @snowflake0531
Then, there is Soh Cah Toa
Sin(x) = opposite/hypotenuse
Cos(x) = adjacent/hypotenuse
Tan(x) = opposite/adjacent
\(\color{#0cbb34}{\text{End of Quote}}\)

Answer 27

Do you know how to do these at all? or do you just not know how to do the questions

Answer 28

just dont know how to answer these questions i have 4 question im struggling with

Answer 29

Okay, but I have make sure, this means you do know how to do the equations?

Answer 30

kinda

Answer 31

Kinda is no lol

Answer 32

Okay, so with those functions
Sin(x) = opposite/hypotenuse
Cos(x) = adjacent/hypotenuse
Tan(x) = opposite/adjacent
we usually use these do find
For sine, opposite side
For cos, adjacent side
For tan, opposite side

Answer 33

An observer (O) is located 900 feet from a building (B). The observer notices a helicopter (H) flying at a 49° angle of elevation from his line of sight. How high is the helicopter flying over the building? You must show all work and calculations to receive full credit. (10 points)

Are you able to draw this out?

Answer 34

no just write the answer in like sentence form

Answer 35

But to do this, you'll need to know what it looks like...
So, I mean, are you able to draw this out?
And then figure out which trigonometric ratio to use

Answer 36

yes but the answer has to wrote in sentence form

Answer 37

Ik.
But can you, right now, use the draw feature, and tell me what the triangle looks like, and label the angles and lengths

Answer 38

Or, I can draw it, if you want?

Answer 39

im no good at drawling on this thing

Answer 40

Do you know which trigonometric ratio you would use?
*Look above what I have previously wrote

Answer 41

which ratio would you use tho

Answer 42

i cant draw lol

Answer 43

I already drew it out for you now...
Just tell me which trigonometric ratio you would use...

Answer 44

tr the cos

Answer 45

tr?
and also, no
We have the adjacent side and opposite side
Which one fits that

Answer 46

sin

Answer 47

\(\color{#0cbb34}{\text{Originally Posted by}}\) @snowflake0531
Okay, so with those functions
Sin(x) = opposite/hypotenuse
Cos(x) = adjacent/hypotenuse
Tan(x) = opposite/adjacent
we usually use these do find
For sine, opposite side
For cos, adjacent side
For tan, opposite side
\(\color{#0cbb34}{\text{End of Quote}}\)

Answer 48

so How do I answe the question

Answer 49

You first have to figure out which ratio it is
We have opposite and adjacent, which ratio is it

Answer 50

how do I do that is this right
if you multiply both sides of the equation by 900 you get

h=900×tan(49), in your figure theta is given as 49 deg, perpendicular = h, and base = 900 ;

so, tan 49 = h/900 , and then find h, so h = 1035

Answer 51

Actually, it would be tan(49) = x/900
soilve for x

Answer 52

so how do I write the answer out and solve

Answer 53

are you still here

Answer 54

Sorryyyyyyyy i was fighting with my brother lmao
so, put into your calculator, make sure it's in degrees and but in
tan(49)(900)

Answer 55

can you just write the answer out so i know what im doing

Answer 56

tan(49)(900)
put that into your calculator..