Question

Can I get some Chemistry help?

Answer 1

@AZ

Answer 2

@AZ

Answer 3

If a reaction follows the rate constant rate = k[A], what would be the units on the rate constant? Group of answer choices L/mol-s s 1/s mol/L-s

Answer 4

If a reaction ALaTeX: \longrightarrow⟶B occurs in a single step and follows the rate law, rate = k[A], which of the following plots would be a straight line?
Group of answer choices

A plot of ln[A] versus time

A plot of 1/[A] versus time

A plot of 1/[A]2 versus time

A plot of [A]2 versus time

Answer 5

That's the second question in picture form

Answer 6

one question at a time haha

Answer 7

Okay my bad, thats just two questions and I had to send a picture of the second one because it messed up in the text.

Answer 8

For the first question, it's something you need to understand and then figure it out or you can just straight up memorize it

reaction rate has units of M/s but the units for the constant, k, will depend on the order of the reaction

so if was a zero order
rate = k * [A]^0
rate = k
so k has the same units as the rate so it would be M/s
(that's Molar which is moles/liter, just in case you weren't aware)

if it was first order, now you have

rate = k * [A]^1

we know the units for rate are M/s and [A] has units of M
so the units for K has to be just 1/s

and similarly for second order

rate = k * [A]^2
M/s = ?? * M^2

and if you divide M^2 on both sides to determine the units of k in a second order reaction, you'll see that the units are 1/(M*s)

so it's just something you need to memorize or if you understand it, something you can just derive and figure out

Answer 9

remember that M = moles of liter

so you can replace that but be careful when dealing with the fractions

Answer 10

So the first question would be L/mol-s

Answer 11

I know its not mol/L-s for a fact.

Answer 12

\(\color{#0cbb34}{\text{Originally Posted by}}\) @kamachavis
So the first question would be L/mol-s
\(\color{#0cbb34}{\text{End of Quote}}\)

That's correct

Answer 13

M^-1 s^-1

and 1/M is going to be 1/(moles/liter) = liters/mole

Answer 14

so good job :)

Answer 15

I have a feeling that the second question is "A plot of 1/[A]^2 versus time"

Answer 16

But I am not sure that is why I came here to check behind myself.

Answer 17

\(\color{#0cbb34}{\text{Originally Posted by}}\) @AZ
so good job :)
\(\color{#0cbb34}{\text{End of Quote}}\)
Thank you!

Answer 18

For your second question, once again, you're going to have to memorize the equations

and then think of the equations as if they're in the form of y = mx + b


t is the variable that changes (basically our 'x') so the slope is going to be k or -k
the other term being added is the constant

and y would be whatever is on the other side of the equal sign

and so the graph would be y vs x

Answer 19

so it would be ln[A]

Answer 20

a plot of ln[a] versus time

Answer 21

\(\color{#0cbb34}{\text{Originally Posted by}}\) @kamachavis
a plot of ln[a] versus time
\(\color{#0cbb34}{\text{End of Quote}}\)

exactly, because it's a first order reaction

Answer 22

Thank you!

Answer 23

You're welcome!