Once she completes a wall, Sabrina notices that the number of squares along each side of the wall is equal to the number of square centimeters in each tile’s area. Write an equation for the number of squares on the wall, SW, in terms of c. Then, solve for the number of squares on the wall. In the previous question the answer to the area of the tiles is 100
Methode of generating random number from bilateral distribution
@AZ idk if i understand it right - maybe something in this way xSW = 100c ???
So building off the actual complete question found here: https://questioncove.com/study#/updates/5ecd592442373adbcae2c40 Here is the complete information regarding this part: Part E After seeing her remodeled bathroom, Paulina’s friend Sabrina also wants to remodel her bathroom. The tile she has chosen is shown below. a square tile in a blue and white checkerboard pattern with four small squares per side If all of the smaller squares have sides c centimeters long, write an expression for the area of the whole tile, AT, and find the area of the tile if the length of the small squares is 2.5 centimeters. Part F Once she completes a wall, Sabrina notices that the number of squares along each side of the wall is equal to the number of square centimeters in each tile’s area. Write and solve an equation for the number of squares on the wall, SW.
So the answer to part E was 100 cm^2 according to OP In Part F We were originally told `number of squares along each side of the wall is equal to the number of square centimeters in each tile’s area.` And we want to `Write an equation for the number of squares on the wall, SW, in terms of c` we know that the smaller squares have sides c centimeter long so the area of the entire tile is (4c)^2 = 16c^2 (which is something you've already determined in part E) SW is how many squares there are on the wall so sqrt(SW) would give us the number of squares along each side of the wall number of square centimeters in each tile’s area would be the area of the tile but none of the numbers make sense to make that original statement true so
@surjithayer would you like to give this question an attempt?
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