Question

math problem

Answer 1

-4 -1

Answer 2

@AZ

Answer 3

@Florisalreadytaken

Answer 4

ok, so as discussed with az recently

x=-4
x=-1

what does that mean?

Answer 5

(x+4) (x+1)

Answer 6

good -- what do we get from that?

Answer 7

im not sure

Answer 8

sorry im not sure

Answer 9

so

y = a(x+4)(x+1)

Answer 10

our y would be the intersection on the y axis

Answer 11

4

Answer 12

yes so we have

4 = a(x+4)(x+1)

Answer 13

alright

Answer 14

but the intersection point is (0 , 4)

thus

4 = a(0+4)(0+1)

Answer 15

a(4)(1)

Answer 16

where

\[4 = a \times 4 \times 1\]

Answer 17

this confusing

Answer 18

alright

Answer 19

solve for a then

Answer 20

1

Answer 21

a = 1

Answer 22

4=4

Answer 23

y = 1(0+4)(0+1) *

Answer 24

4 = 4

Answer 25

what?

Answer 26

y = 4

Answer 27

What u need help with

Answer 28

florisalreadytaken y = 4

Answer 29

does that sound right?

Answer 30

im not sure

Answer 31

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Florisalreadytaken
y = 1(0+4)(0+1) *
\(\color{#0cbb34}{\text{End of Quote}}\)

what do we get from this tho -- to turn it into a parabola form

Answer 32

im not sure

Answer 33

we get that

y = 1(x+4)(x+1)

Answer 34

from where we simplify that into

x^2 + 5x + 4

Answer 35

and yeah thats it

Answer 36

thanks

Answer 37

let eq. of parabola be
y=ax^2+bx+c
beacuse it passes through (-4,0),(-1,0) and (0,4)
so 0=16a-4b+c
0=a-b+c
4=0a+0b+c
so c=4
16a-4b+4=0
4a-b+1=0
4a-b=-1 ...(1)
a-b=-4 ...(2)
subtract
3a=3
a=3/3=1
a=1
1-b=-4
b=1+4=5
so reqd. eq. is
y=x^2+5x+4

Answer 38

thanks

Answer 39

yw