The figure shows Angel Stadium of Anaheim and the triangle formed by home plate, the right center field fence, and third base. In the figure, the approximate distance from the right center field fence to third base is 339.4 ft. https://prnt.sc/11932ho Outline a plan for how you are going to determine the distance x from home plate to the right center field fence. Implement your plan
Im not sure how to start
first i would begin with using law of sin?
|dw:1618077211057:dw| we wouldn't use law of sines, we would have to use law of cosines do you know the law of cosines?
Well I guess, you could also use law of sines but it's up to you
I havent learned about that
But you have learned of law of sines?
Yes
Okay, let's use that then You can see the triangle that we have. Keep in mind that it is NOT a right angle triangle First, let's figure out the angle a first |dw:1618077463487:dw|
Law of sine: \(\Large \frac{\sin A}{a}=\frac{\sin B}{b}=\frac{\sin C}{c} \) can you set it up to find the angle 'a' because we know that the side opposite angle 63.4 is 339.4 feet And we know that one side has 90 feet so we need to first find the angle opposite 90 feet and then we can find the third angle because all the angles of a triangle add up to 180 and then we can use law of sine again to calculate the missing side does that make sense?
yes
so let me know what you get then
idk i keep getting -52
How? and for what? Show your work
i mean 209 (sin x)/(90)=(sin339.4)/(63.4)
339.4 is the length of the side... not the angle sin a / 90 = sin 63.4 / 339.4 solve for 'a'
so 16 is the side length
that would be the angle though
How did you get 16?? \(\Large \sf \dfrac{\sin (a)}{90} = \dfrac{\sin (63.4)}{339.4}\)
Remember to also be in degrees and not radians what is sin 63.4 degrees divide it by 339.4 then multiply both sides by 90 and then you have sin(a) = ?? and then take the arcsin of both sides (and remember to be in degrees and not radians)
so how i see @iosangel gave up ... is offline
13.7
That is correct so now you have |dw:1618089528474:dw| Now can you calculate the third angle of the triangle? Remember that they all add up to 180
102.9
Now use the law of sine to find what 'x' is \(\dfrac{\sin 63.4}{339.4} = \dfrac{\sin 102.9}{x}\)
369.9
370 ft
There you go
Thank you for your Patience and time
It was my pleasure!
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