Question

Expanding Logarithms

Answer 1

@AZ

Answer 2

Almost but not quite

Answer 3

It's wrong, just not sure what part

Answer 4

You need to use this rule:
\( log (a^b) = b\cdot log(a)\)

So you have x^3 so what happened to that 3?

Answer 5

AH 1/3

Answer 6

Some of the other logarithm laws that you used correctly

\( log(xy) = log(x) + log(y)\)

\( log\left(\dfrac{a}{b}\right) = \dfrac{log(a)}{log(b)}\)

Answer 7

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Allison
AH 1/3
\(\color{#0cbb34}{\text{End of Quote}}\)

No no, check again

Answer 8

\( log (\color{red}{a}^\color{orange}{b}) = \color{orange}{b}\cdot log(\color{red}{a})\)


\( log (\color{red}{x}^\color{orange}{3}) = ?? \)

Answer 9

I got it wrong, it's gone now

Answer 10

):

Here's how to solve it for any future problems

\( log\left(\dfrac{\sqrt[3]{y} x^3 }{z}\right) = log(\sqrt[3]{y}x^3) - log(z)\)

\( = log(\sqrt[3]{y}) + log(x^3) - log(x)\)

\( = \dfrac{1}{3}log(y) + 3~log(x) - log(z)\)

Answer 11

Thank you

Answer 12

3fwan

Answer 13

My God, you're Arab