Question

math problem

Answer 1

@Florisalreadytaken

Answer 2

@snowflake0531

Answer 3

ok we did a similar to this one ere earlier

this is what its stated
\[ y \propto x^2\]

Answer 4

alright

Answer 5

whys the infinity symbol broken

Answer 6

infinity symbol? LOL! -- it stands for "directly proportional to".

Answer 7

alright whats next

Answer 8

We must convert that, into an equation by adding the constant of variation (k).
\[ y=k \times x^2 = kx^2 \]
we are given some conditions -- can you determine them?

Answer 9

it stands for directly propotional to

Answer 10

what is y when x =7?

Answer 11

\(\color{#0cbb34}{\text{Originally Posted by}}\) @klmjnmkj
what is y when x =7?
\(\color{#0cbb34}{\text{End of Quote}}\)
no -- we leave that for later

so the condition that we are given is

x=2

y=2

\[y=k x^2 \Rightarrow k=\frac{y}{x^{2}}=\frac{2}{2}=1 \]
and thats why:

`y=1x^2`

Answer 12

i see

Answer 13

can you notice the mistake i made?

Answer 14

you didn't write 2/2^2

Answer 15

yes!
so it would be\( \frac{2}{4} = 0.5\) so thats why \(y=0.5x^2\)

Answer 16

the ansers 0.5x^2 ?

Answer 17

no wait

Answer 18

now we have to look at the 2nd conditions -- to find the value for y

Answer 19

alright

Answer 20

step one

Answer 21

you can see that the formula we will use is \( y=0.5x^2
\)

where

x=7

so:
\[ y=0.5 \times 7^2=... \]

Answer 22

m

Answer 23

24.5

Answer 24

yes -- so the answer would be
\[ y=24.5 \]