I REALLY need an explanation on how to solve this problem, the instructors suck at their job of explaining the math At Mountain High School, the students were surveyed about their participation in band (B) and track (T). The results of the survey are shown in the Venn diagram. Circles B and T intersect. Circle B contains 24, circle T contains 31, and the intersection contains 9. Number 14 is outside of the circles. Given that a randomly chosen student participates in band, what is the probability that the student also participates in track?
Diagram (if needed)
so how many people participate in band?
so the probability is P(track given band)
so P(t | b) = P(t and b)/P(b)
P i think
"Given that a randomly chosen student participates in band, " - There are 24 + 9 = 33 people in B. The "given" means you have definitely chosen one of those. "what is the probability that the student also participates in track?" - There are 9 of those 33 also in T Yes?
\(\color{#0cbb34}{\text{Originally Posted by}}\) @1234Bored tbh i need 2 level up \(\color{#0cbb34}{\text{End of Quote}}\) then do that.
The Venn diagram is not included, so I am going to explain the procedure and you will be able to calculate the result just plugging the numbers. From Vend diagram you will be able to conclude two numbers: the total number os students surveyed that participate in band (B) the total number of students surveyed that participate in track (T) the total number of students surveyed that participate in both band (B) and track (T) = B∩T the total number of students surveyed, which is: total number of students in band B + total number of students in track - less the number of students that participate in both. = B + T - (B∩T) So, the probability that one student that participate in band (B) also participate in track (T) = Number of students that participate in both / number of students that participate in band = (B∩T) / B Now, you just have to find B∩T and B from the diagram and plugg in into the formula (B∩T)/B. That's it.
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