agian sorry guys pythagorean theorem
@MrMudd183
So here's what I would do in this... They provide a grid on this problem, so count up the units between each line the plots fall on. I will do an example on the provided picture
So after we count the distance between the plots, we have the units for A^2 and B^2 Now the order you place them in doesn't matter
\(\color{#0cbb34}{\text{Originally Posted by}}\) @MrMudd183 So after we count the distance between the plots, we have the units for A^2 and B^2 Now the order you place them in doesn't matter \(\color{#0cbb34}{\text{End of Quote}}\) ight so it wuld be 5² +3²=2²
Not quite
The triangle is 5 units across, and 2 units upwards
ohh
After that, you would square the 2 and 5 then add them together to get C whenever it's squared....to find the true answer, you would have to take the squareroot of the product of A and B after you square them and add them
huhhhhhhh
u gotta dumb that down for me
Let me rephrase After you add square A & B, and after you add them together, that will give you the product of C whenever it's squared To find the true unit measurement, you would have to take the squareroot of C
sooo 2²+5² then go on
\(\color{#0cbb34}{\text{Originally Posted by}}\) @xxcoffee sooo 2²+5² then go on \(\color{#0cbb34}{\text{End of Quote}}\) First you square the 2, then square the 5
kk
After you square them, you add them together to get the squared product of C
ohh
And to find the actual product of C, you would have to take the squareroot of it
5.38 ?
noo 5.4
\(\color{#0cbb34}{\text{Originally Posted by}}\) @xxcoffee noo 5.4 \(\color{#0cbb34}{\text{End of Quote}}\) Yep, correct
\(\color{#0cbb34}{\text{Originally Posted by}}\) @MrMudd183 \(\color{#0cbb34}{\text{Originally Posted by}}\) @xxcoffee noo 5.4 \(\color{#0cbb34}{\text{End of Quote}}\) Yep, correct \(\color{#0cbb34}{\text{End of Quote}}\) yayy
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