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Find the x‐value for point C such that AC and BC form a 2:3 ratio.
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@Tyrion
@Conner4789
@snowflake0531
It's a fact that if AC:BC = 2/3, then x-diff of A to C : x-diff of B to C = 2:3, and same with the y value
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though the problem wants the x value of C
So the x-value of A is -3, and the x-value of B is 3 let the x-value of C just be x
So the distance from -3 to x : the distance from x to 3 = 2/3
so here, we get (x - (-3)) : (3 - x) = 2:3
So (x+3) : (3-x) = 2:3 which you can rewrite as fractions \[(x+3)/(3-x) = 2/3\]
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Cross multiplying gets you 3(x+3) = 2(3-x) 3x+9 = 6-2x 5x = -3 x = -0.6
hope that helped!
i did thank you soooo much
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