A bicycle manufacturing company makes a particular type of bike. Each child bike requires 4 hours to build and 4 hours to test. Each adult bike requires 6 hours to build and 4 hours to test. With the number of workers, the company is able to have up to 120 hours of building time and 100 hours of testing time for a week. If c represents child bikes and a represents adult bikes, can the company build 20 child bikes and 6 adult bikes in a week.

Question

flawdababynai · Answer

please help

Extrinix · Answer

Ok so, 
$4~hrs~to~build~,~4~hrs~to~test$ = 8 hrs in total for a child's bike
$6~hrs~to~build~,~4~hrs~to~test$ = 10 hrs in total for an adult bike

so for this you would divide the amount of hours of building (let's say $b$) by the amount of hours to build a childs bike ($c$) + an adult bike ($a$)

$\frac{b}{c+a}$

now, enter the information in

$\frac{120}{4+6}$
simplify

$\frac{120}{10}$ = __

do the same for the amount of testing,
$\frac{100}{4+4}$

$\frac{100}{8}$

now figure those out, then multiply the hours to build answer by 26 and see if it ends up less than 120

$build~time \times 26<120$

and then do the mount of testing

$test~time \times 26<100$

if both of those are lower then or equal to 120 and 100 then the bikes can be completed, if not, they cant be completed.