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Mathematics 10 Online
snowflake0531:

@AZ healp

snowflake0531:

Like, I need a way to do this without using a calculator

AZ:

This is going to be a long one lool \( \cos (a - b) = \cos (a) \cos (b) + \sin (a) \sin (b)\)

snowflake0531:

So should I plug all of htat in o-o

AZ:

Have you learned the inverse trigonometric functions yet?

1 attachment
JamesTDG:

AZ, I'll leave the post to you, I am not that equipped to help with trig...

snowflake0531:

@az wrote:
Have you learned the inverse trigonometric functions yet?
Nope-

AZ:

Well if they're asking you this question, then you're expected to know it hmm

JamesTDG:

If it is a site like edgenuity, they sometimes exclude stuff or put questions on the wrong assignments. I might flag that problem to your teacher so that it can be resolved

snowflake0531:

But btw for the thingy \[[\cos(\tan ^{-1}\frac{ 5 }{ 12 })][\cos(\cos ^{-1}\frac{ 4 }{ 5 })] + [\sin(\tan ^{-1}\frac{ 5 }{ 12 })][\sin(\cos ^{-1}\frac{ 4 }{ 5 })]\]

AZ:

so obviously \( \cos (\cos^{-1} x) = x\) and then use the formulas in that screenshot

snowflake0531:

ye, give me a moment xd

snowflake0531:

\[(\frac{ 1 }{ \sqrt(1+\frac{ 25 }{ 144 }) })(\frac{ 4 }{ 5 })+(\frac{ \frac{ 4 }{ 5 } }{ \sqrt(1+\frac{ 16 }{ 25 }) })(\sqrt(1-\frac{ 16 }{ 25 })\]

snowflake0531:

And then that would simplify to \[\frac{ 1 }{\sqrt( \frac{ 169 }{ 144 }) }(\frac{ 4 }{ 5 })+(\frac{ \frac{ 4 }{ 5 } }{ \sqrt(\frac{ 41 }{ 25 }) })(\sqrt \frac{ 9 }{ 25 }\]

snowflake0531:

not simplify more like-, change to

snowflake0531:

which and then goes to \[(\frac{ 1 }{ \frac{ 13 }{ 12 } })(\frac{ 4 }{ 5 })+(\frac{ 4 }{ 5 })(\frac{ 1 }{ \sqrt(\frac{ 41 }{ 25 } )})(\frac{ 3 }{ 5 })\]

snowflake0531:

and i could simplify the rest but how woudl i get rid of hte sqrt41/25

AZ:

\[ \left(\frac{ 1 }{ \sqrt{1+\frac{ 25 }{ 144 }} }\right) \left(\frac{ 4 }{ 5 }\right) +\left(\frac{ \frac{ 4 }{ 5 } }{ \sqrt(1+\color{red}{\frac{ 25 }{ 144 }}) }\right)\left(\sqrt{1-\frac{ 16 }{ 25 }}\right)\]

snowflake0531:

oh

snowflake0531:

ohhhh oopsssssssssss

snowflake0531:

So it would be \[(\frac{ 12 }{ 13 })(\frac{ 4 }{ 5 }) + (\frac{ 4 }{ 5 })(\frac{ 12 }{ 13 })(\frac{ 3 }{ 5 })\]

AZ:

\[ \left(\frac{ 1 }{ \sqrt{1+\frac{ 25 }{ 144 }} }\right) \left(\frac{ 4 }{ 5 }\right) +\left(\frac{ \frac{ 4 }{ 5 } }{ \sqrt{1+\frac{ 25 }{ 144 }} }\right)\left(\sqrt{1-\frac{ 16 }{ 25 }}\right)\] \[ \left(\frac{ 1 }{\dfrac{13}{12} }\right) \left(\frac{ 4 }{ 5 }\right) +\left(\frac{ \frac{ 4 }{ 5 } }{ \dfrac{13}{12} }\right)\left(\dfrac{3}{5}\right)\]

AZ:

@snowflake0531 wrote:
So it would be \[(\frac{ 12 }{ 13 })(\frac{ 4 }{ 5 }) + (\frac{ 4 }{ 5 })(\frac{ 12 }{ 13 })(\frac{ 3 }{ 5 })\]
Yup

snowflake0531:

and tehn i got 384/225?

AZ:

@snowflake0531 wrote:
and tehn i got 384/225?
325

AZ:

not 225

snowflake0531:

oh oops

snowflake0531:

okay done thankssssssssssssssssssssssssssssssssssssss so much xd

AZ:

You're welcome!

AZ:

@az wrote:
\[ \left(\frac{ 1 }{ \sqrt{1+\frac{ 25 }{ 144 }} }\right) \left(\frac{ 4 }{ 5 }\right) +\left(\frac{ \frac{ 4 }{ 5 } }{ \sqrt(1+\color{red}{\frac{ 25 }{ 144 }}) }\right)\left(\sqrt{1-\frac{ 16 }{ 25 }}\right)\]
oh I forgot to correct the numerator to be 5/12 and not 4/5

snowflake0531:

wdym

AZ:

\[ \left(\frac{ 1 }{ \sqrt{1+\frac{ 25 }{ 144 }} }\right) \left(\frac{ 4 }{ 5 }\right) +\left(\frac{ \frac{ 5 }{ 12 } }{ \sqrt{1+\frac{ 25 }{ 144 }} }\right)\left(\sqrt{1-\frac{ 16 }{ 25 }}\right)\] \[ \left(\frac{ 1 }{\dfrac{13}{12} }\right) \left(\frac{ 4 }{ 5 }\right) +\left(\frac{ \frac{ 5 }{ 12 } }{ \dfrac{13}{12} }\right)\left(\dfrac{3}{5}\right)\]

AZ:

@snowflake0531 wrote:
wdym
the one in red, the numerator should 5/12

AZ:

so (12/13 * 4/5) + (5/12 * 12/13 * 3/5)

snowflake0531:

so i got 756/780

AZ:

nope nope, do it again you'll get the answer you shared in DMs with me

snowflake0531:

oh, it simplifies to that 63/65 lol

AZ:

exactly

snowflake0531:

xddd thanksssssssss

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