can anyone find the answer to this?
(x^2-6x-4)+(2x^2-3x+5)

Question

boredfr · Answer

Ok so lets write this in a way that is easier to understand first

$$(x^{2}-6x-4)+(2x ^{2}-3x+5)$$

Ok so next we are going to combine like terms

boredfr · Answer

So

$$(x ^{2}+2x ^{2})+(-6x+-3x)+(-4+5)$$

End product of

$$(3x ^{2}+-9x+1)$$

boredfr · Answer

@creed wrote:

Equation; $$(x^2-6x-4)+(2x^2-3x+5)$$ Now by using the sequence of combing like terms; You will use the numbers and variables to combine terms; Combine the "x-values with the square on the x's"; $$(3x^3-6x-4)+(-3x+5)$$ Combine varible "x" ; $$(3x^3-9x-4)+(5)$$ Combine last numbers; $$(3x^3-9x+1)$$ Finished! $$(3x^3-9x+1)$$

The exponent is 2 not 3

boredfr · Answer

I didn't

darkknight · Answer

like terms for example same base same exponent can be added together
 $$2x^2+x^2=3x^2$$ so boredfr is correct, you dont add exponents when you are adding

boredfr · Answer

No problem ._.

Creed · Answer

Thank you dark knight for your time.

darkknight · Answer

No Problem