How do I solve these two system of equations algebraically? y = x^2 + 3x + 5 y = x + 13

Step 1: Add the two equations. Step 2: Solve for x. Step 3: To find the y-value, substitute in 3 for x in one of the equations. Step 4: Solve for y.

._. huh?

thats how

im confused-

sorry i realy dont no these good

bruh

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stop spamming

sorrry

We can do this the same we do linear equations \[y=x^2+3x+5\] \[y=x+13\] We have \[x^2+3x+5=x+13\] can you get them to one side of the equation and factor it?

I can try ;-;

smart

you got this

actually no, I cant

... just get them to one side of the equation make it __________=0

ohhh

x^2 + 2x - 8 = 0

Yes so I know that you're terrible at factoring, and I don't feel like being in the mood to spend the time to talk we have (x-4)(x+2) which makes x =4 and x=-2

thank youuuu

that isn't hte answer... now find y

how do I find y :I

You have (4,_) and (-2,_) so plug these x values into y=x+13

ohhh y = 4 + 13 y = 17 ..?

Yes so (4,13) and now do it for -2

Wait wait wait shoot

(-4,_) and (2,_)

So plug those 2 into y=x+13

ah ok, y = 15

Yes that's for 2, how about -4

and y = 9

Yes so there are your answers (-4,9) and (2,15)

yay tysm

yw~

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