Question

How do I solve these two system of equations algebraically?

y = x^2 + 3x + 5
y = x + 13

Answer 1

Step 1: Add the two equations. Step 2: Solve for x. Step 3: To find the y-value, substitute in 3 for x in one of the equations. Step 4: Solve for y.

Answer 2

._. huh?

Answer 3

thats how

Answer 4

im confused-

Answer 5

sorry i realy dont no these good

Answer 6

bruh

Answer 7

stop spamming

Answer 8

sorrry

Answer 9

We can do this the same we do linear equations

\[y=x^2+3x+5\] \[y=x+13\]

We have
\[x^2+3x+5=x+13\]
can you get them to one side of the equation and factor it?

Answer 10

I can try ;-;

Answer 11

smart

Answer 12

you got this

Answer 13

actually no, I cant

Answer 14

...
just get them to one side of the equation make it __________=0

Answer 15

ohhh

Answer 16

x^2 + 2x - 8 = 0

Answer 17

Yes so I know that you're terrible at factoring, and I don't feel like being in the mood to spend the time to talk
we have
(x-4)(x+2)
which makes x =4 and x=-2

Answer 18

thank youuuu

Answer 19

that isn't hte answer...
now find y

Answer 20

how do I find y :I

Answer 21

You have
(4,_) and (-2,_)
so plug these x values into y=x+13

Answer 22

ohhh

y = 4 + 13
y = 17

..?

Answer 23

Yes so
(4,13)

and now do it for -2

Answer 24

Wait wait wait shoot

Answer 25

(-4,_)
and
(2,_)

Answer 26

So plug those 2 into y=x+13

Answer 27

ah ok, y = 15

Answer 28

Yes that's for 2, how about -4

Answer 29

and y = 9

Answer 30

Yes so there are your answers
(-4,9) and (2,15)

Answer 31

yay tysm

Answer 32

yw~