Question

math problem

Answer 1

@minustempo

Answer 2

@snowflake0531

Answer 3

@darkknight

Answer 4

https://questioncove.com/users/darkknight#/updates/606b831e88a1242fd23b3800

Answer 5

i made a tutorial, please use it

Answer 6

i think you did post this same particular question a while ago... i thought you did it by yourself!

anyway; were asked to turn \(f(x)= \log(x)\) into \(f(x) = c \times \log(x)^{ax}+b\)

1) stretch vertically by 7.
2) reflect over the y axis.
3) shift up 3 units.

ok, so lowe me finish the whole ting in 1 go -- please, look at the table i just attached there at the bottom AND darkknight's post; use that information for all the other same type of questions :D

lets start shall we -- we have to vertically stretch by 7 which means: \( f(x)=\color{mediumaquamarine}{c} \times \log(x) \). by plugging in 7 for c, it would be:

\[ \large f(x)=\color{mediumaquamarine}{7} \times \log(x) \]
secondly, we are asked to reflect across the y axis -- that means we change the operator of x to its opposite: by doing that, we get:

\[ \large f(x)= 7 \times \log( \color{tomato}{-} x ) \]
and lastly, we have to shift up 3 units: \( f(x)= c \times \log(-x) \color{lightskyblue}{+b} \)
so by adding that, we put an end to the whole thing -- SO, the final answer is:

\[ \Large f(x)= \color{mediumaquamarine}{7} \times \log( \color{tomato}{-} x) \color{lightskyblue}{+3} \]