Question

The table shows the weights of giant pumpkins grown in two towns, Cedartown and Baytown. Match each phrase to its value.

Weight of Cedartown
Pumpkins (pounds) Weight of Baytown
Pumpkins (pounds)
611 584
753 622
575 713.5
685.5 579
718 644
20.2
40
40.2
60.4
575
628.5
668.5
713.5
the average weight of pumpkins
grown in Cedartown
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the average weight of pumpkins
grown in Baytown
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the mean absolute deviation
of the pumpkin weights in
Cedartown
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the mean absolute deviation of
the pumpkin weights in Baytown
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Answer 1

Can you provide a screenshot of the chart for us please.

Answer 2

with the numbers being all in a row, we can not direct you into working it, if the numbers arent seperated.

Answer 3

do you know how to find average?

Answer 4

hen finding an average of set numbers, you would begin by adding all of the numbers in a set, and then dividing the sum by the amount of numbers in the set

Answer 5

So basically take all of the numbers of Cedartown and add them, then divide the sum of those numbers by 5

\(611+753+575+685.5+718=X\)

so \(3342.5=X\)

then we take that and divide it by 5
so \(\dfrac{3342.5}{5}\)

that gives you youre answer for the first question.
You can do the same to find question 2 that way.

now to find the mean absolute deviation of the two towns, do this:

I made up an equation for this, \(x= \dfrac{v-m}{t}\)
now to do mean absolute deviation, you find the mean listed in the first 2 questions, then take that and find how far from the mean each number is, so for instance the first number listed in Cedartown,
\(611 \rightarrow \dfrac{611-668.5}{5}\)
now, do that for each value then add all of your answers together and divide by 5
\(\dfrac{477.3+v2+v3+v4+v5}{5}=x\)

once you solve the last part, you have your answer for Cedartown, then do the same for Baytown.

Answer 6

If you need any help, just leave a comment and I'll assist you.