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PLs help quesion as photo in replies
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Can anyone help me understand
We want to simplify it.. so the denominator doesn't have an i (a-bi)(a+bI) = a^2 + b^2 Can you make the denominator a rational number what is (3-2i)(3+2i)
13 right?
nope i think i messed it up
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Yes so now we also have to multiply the top by that \[\frac{ 3-i }{ 3-2i } = \frac{ (3-i)(3+2i) }{ (3-2i)(3+2i) } = \frac{ ? }{ 13 }\] what is the question mark
I got it form here thx.
yw~
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