the airplane door is 19 feet off the ground and the ramp has a 31 degree angle of evaluation. what is the length y of the ramp?
@AZ
Let's draw the image, okay? |dw:1619836309530:dw|
ok
Does that make sense? The ramp is on the ground and at an angle of 31 degrees to reach the door which is 19 feet high and we want to calculate the length of the ramp
yeah but how
Have you learned about sin cos or tan?
yes but i dont get it
Sure, we can cover it again
Have you ever heard of SOH CAH TOA Essentially, it's an acronym to help you remember the trigonometric functions sin of an angle equals the opposite side over the hypotenuse We write that as sin \(\theta\) = opposite/hypotenuse Do you see the initials? Sin = Opposite/ Hypotenuse SOH Similarly, for cosine and tangent cos \(\theta\) = adjacent/hypotenuse CAH tan \(\theta\) = opposite/adjacent TAH
are you a teacher
Here's an image to help you see it together
ok
No haha, I'm just a student like you :)
cool:)
So in the image I drew, do you see that \(\theta\) is going to be the angle which is 31 We're looking for the length of the ramp which is the hypotenuse And we know the side opposite of the angle So would we use sin, cos, or tan?
ok
im sorry but its late can you just tell me the answer and we can go over it tomorrow
I would love to but the purpose of this site is to help teach and learn. If I gave you the answer, I'd be breaking the rules and get in trouble It'll only take like 3 minutes if you work with me to get to the correct answer!
ok
Remember sin = opposite / hypotenuse cos = adjacent / hypotenuse tan = opposite / adjacent we know the side OPPOSITE to the angle and we want to know the hypotenuse which one do we use? which one has both the opposite and the hypotenuse
sin?
Exactly! So remember how we set it up? \(\sin \theta = \dfrac{\text{opposite}}{\text{hypotenuse}}\) so our angle or \(\theta\) is 31 and the side opposite is 19 do you know how to solve for the hypotenuse? (You have to use a calculator to find sin 19 by the way)
no how do you put into calculator
You can use Google but you have to be careful that you're doing sin 31 degrees otherwise it'll do 31 radians which is not what we want so https://www.google.com/search?q=sin+31+degrees
So what is sin 31 degrees = ?
0.5150
??
Good! So now we have \(\sin \theta = \dfrac{\text{opposite}}{\text{hypotenuse}}\) \(\sin 31^o = \dfrac{19}{\text{hypotenuse}}\) \( 0.5150 = \dfrac{19}{\text{hypotenuse}}\) and think of the hypotenuse like it's an 'x' \( 0.5150 = \dfrac{19}{x}\) How would you solve for x?
why do i need t solve for x its just y
oh wait nvm haha
im so dumb
i dont know how to solve for x
haha yeah, we can use any letter but 'x' is the one that's most commonly used in math
so 0.52 is the answer cause you round it to the tenth place
That's not a problem \( 0.5150 = \dfrac{19}{x}\) So we have 'x' in the denominator. What happens if we multiply 'x' on both sides So essentially, how would you simplify \( 0.5150 \times x= \dfrac{19}{x} \times x\)
ok so how would you simplify it
true
yeah
So we're left with 0.5150 * x = 19 can you solve for x now?
no how do you put that in a calculator
uhh you wouldn't be able to put it into a normal calculator but this is something you should be able to do on your own now
im dumb trust me i cant
you want to get 'x' all by itself right now, it's being multiplied with 0.5150 so to get x all by itself, and essentially move the 0.5150 to the other side, you have to do the opposite of multiplication what is the opposite of multiplication?
division
Exactly!! So we divide 0.5150 on both sides So all you need to do is divide 19 by 0.5150 x = 19 / 0.5150 x = ??
36.9
There you go!
thank you so much ill keep in touch
Of course! You're welcome!
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