Question

help pleas(ss below)

Answer 1

@aaronlloyd

Answer 2

The distance between two points P=(px,py) and Q=(qx,qy) is d=(qx−px)2+(qy−py)2−−−−−−−−−−−−−−−−−−√.

We have that px=−2, py=5, qx=4, qy=−2.

Thus, d=(4−(−2))2+(−2−5)2−−−−−−−−−−−−−−−−−−−√=85−−√.

Answer 3

._.

Answer 4

by any chance could u break that down?

Answer 5

yes how do u want me to break it down

Answer 6

i honestly have no idea xd

Answer 7

OHHHH nevermind i figured it out

Answer 8

thanks man

Answer 9

np man

Answer 10

\[d=\sqrt{(4-(-2))^2+(-2-5)^2}=\sqrt{36+49}=?\]