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crispyrat:

A guide to sqrt and cbrt

crispyrat:

So first of all what is a sqrt? To put it simply, a square root is the number that can multiply itself by twice to get the desired answer. For example the square root of 64 is 8 or 8 as 8*8=64 and -8*-8 is 64.

crispyrat:

A square root can be a negative however the number inside the square root can also be, but it would require imaginary numbers in which i^2=-1 so sqrt(-36) would be 6i. As 6*i*i*6=36*-1=-36. To find the sqrt of a fraction you would find the sqrt of the numerator and then the sqrt of the denominator. For example: sqrt(100/9)-->10/3 as 10/3*10/3=100/9.

crispyrat:

Next, what about when a number cannot be sqrted? First you would split the number you have into two factor parts: the part that you can sqrt and the part you can't, sqrt the part you can and put it outside leave the rest inside. For example sqrt(18) in which 18 itself is not but if you split it into sqrt(9*2) then you have 3sqrt(2). Here is a list of the squares of numbers up to 12: 1*1=1 2*2=4 3*3=9 4*4=16 5*5=25 6*6=36 7*7=49 8*8=64 9*9=81 10*10=100 11*11=121 12*12=144

crispyrat:

Now cbrt is essentially the same however its the number multiplied 3 in a row. So everything should be adjusted accordingly, for example cbrt(18) would remain this way as 18=3*3*2 and as you can see no number happens 3 times. Also the number inside a cbrt can be a negative as three negatives multiplied will be a negative. For example cbrt(-27)=-3*-3*-3! A list of cubes up to 10(google calculator was used): 1*1*1=1 2*2*2=8 3*3*3=27 4*4*4=64 5*5*5=125 6*6*6=216 7*7*7=343 8*8*8=512 9*9*9=729 10*10*10=1000

crispyrat:

@xxquintonxx is this good? should i add anything :)

crispyrat:

also if u want to request a subject feel free to comment just keep it on topic :)

xXQuintonXx:

e.e give me a sec to read it all

xXQuintonXx:

xd

crispyrat:

cool since u seem to be on this unit u could bookmark this or sumthing e.e

xXQuintonXx:

yup its all good thank you :)

crispyrat:

yw :))))

xXQuintonXx:

@crispyrat wrote:
cool since u seem to be on this unit u could bookmark this or sumthing e.e
ehhhh not really im kinda just all over atm bc im doing some review thing rn

crispyrat:

ah i see is there anything you need help with :)?

xXQuintonXx:

cuz i did 1 thing for sqrt then it jumped me to coordinate stuff then now I'm in angel stuff XD

crispyrat:

i see do u need help with coordinates :p was thinking of doing one

xXQuintonXx:

no im good you have refreshed my mind on how to do em

crispyrat:

haha cool yw :))))

Extrinix:

@crispyrat I recommend using latex... Sqrt: `\(\sqrt{16}\)` \(\rightarrow\) \(\sqrt{16}\) `\(\sqrt{\dfrac{1}{6}}\)` \(\rightarrow\) \(\sqrt{\dfrac{1}{6}}\) Cbrt: `\(\sqrt[3]{16}\)` \(\rightarrow\) \(\sqrt[3]{16}\) Multiply: `\(2 \times 3\)` \(\rightarrow\) \(2 \times 3\)

xxcoffee:

@vibes

crispyrat:

?

crispyrat:

oh vibes already saw the post lol he gave me a medal

xXQuintonXx:

oh lol

crispyrat:

if u have any tutorial requests feel free to leave a post :))))

snowflake0531:

My only request is for you to use latex <.< like what @extrinix said

abbyluvspuppiessssss:

thx!

JamesTDG:

It would be helpful to have a few HS geometry guides

FexrlessRxby:

Bro, this person should be a teacher if he/she isn't already.

crispyrat:

@fexrlessrxby wrote:
Bro, this person should be a teacher if he/she isn't already.
ahaha thanks man

FexrlessRxby:

Lol, np.

Ashtiel:

:p

FexrlessRxby:

Eh?

Astrid1:

Thank you for the help. The user's will appreciate this (: Especially the newbs.

crispyrat:

ok would yall be intrested in a tutorial on coordinates? it may take some more time cus i wanna try latex

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