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Mathematics 21 Online
Joe348:

math again :(

Joe348:

1 attachment
new2luv:

this one I don't know how to help with sorry

Rival:

?Which One do you think it is

Joe348:

alrighty then and um thts why im asking?

ItzAgar:

even tho i dont know this ill try to help you.

Joe348:

I think it is D

Debrus:

hmm lets find the m of arc BA first, and from that, we can find the arc of the rest of the circle circumference \[ \theta = \frac{1}{2} m\overset{\huge\frown}{BA} \] \[ \theta = A = 74^o \] \[ 74^o = \frac{1}{2} m\overset{\huge\frown}{BA} \] \[ m\overset{\huge\frown}{BA} = 74^o \cdot 2 \] \[ m\overset{\huge\frown}{BA} = ? \]

Joe348:

right 148

Debrus:

@Joe348 ? \[ m\overset{\huge\frown}{BA} = 148^o \] we know that the whole circumference of the icrcle is \( = 360^o \) now that we know that, we can subtract \(148^o\) off the \( 360^o \) : \[ 360^o - 148^o = \text{ answer.} \]

Joe348:

ohhh okay

Joe348:

212?

Debrus:

yes.

Joe348:

Okay thanks dude

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