\[(x-2)^2-9=72\]
Well, It firstly asked for an exact method. So let's do that first.
\[x^2+4-9=72\]
Combine like terms;
\[x^2-5=72\]
Add 5 to the 72.
\[x^2=77\]
\[x=8.78\]
Imagine:
That is the approximate soultion~ not the exact*
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Imagine:
Snow- could you finish the question, please.
tyvm
snowflake0531:
uh I think you did it wrong
Someoneee:
The first thing I did was add 9 to both sides of the equation, cancelling the 9 and turning the 72 into 81. Then I'm left with (x-2)^2 = 81 I want to know what I should do next.
Someoneee:
-9*
snowflake0531:
@someoneee wrote:
The first thing I did was add 9 to both sides of the equation, cancelling the 9 and turning the 72 into 81. Then I'm left with (x-2)^2 = 81 I want to know what I should do next.
Yea you're correct this xd
So you can square root both sides to -9 and positive 9 \[x-2 = \pm 9\] so then solve for both solutions
I don't think that there are any 'approximate solutions' in this o-O
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snowflake0531:
Or you can do it the quadratic formula way, factoring the square out, and them making it into the form ax^2 + bx + c, in that way, you'll make more sense of the plus nad minus thing