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Mathematics 21 Online
Someoneee:

Screenshot is in the comments. (X-2)^2-9=72

Someoneee:

Imagine:

Are you asking how to solve this equation?

Someoneee:

Yes. Using the square root method.

Imagine:

\[(x-2)^2-9=72\] Well, It firstly asked for an exact method. So let's do that first. \[x^2+4-9=72\] Combine like terms; \[x^2-5=72\] Add 5 to the 72. \[x^2=77\] \[x=8.78\]

Imagine:

That is the approximate soultion~ not the exact*

Imagine:

Snow- could you finish the question, please. tyvm

snowflake0531:

uh I think you did it wrong

Someoneee:

The first thing I did was add 9 to both sides of the equation, cancelling the 9 and turning the 72 into 81. Then I'm left with (x-2)^2 = 81 I want to know what I should do next.

Someoneee:

-9*

snowflake0531:

@someoneee wrote:
The first thing I did was add 9 to both sides of the equation, cancelling the 9 and turning the 72 into 81. Then I'm left with (x-2)^2 = 81 I want to know what I should do next.
Yea you're correct this xd So you can square root both sides to -9 and positive 9 \[x-2 = \pm 9\] so then solve for both solutions I don't think that there are any 'approximate solutions' in this o-O

snowflake0531:

Or you can do it the quadratic formula way, factoring the square out, and them making it into the form ax^2 + bx + c, in that way, you'll make more sense of the plus nad minus thing

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