Question

Calculate the excluded values of the function

f(x)=1x2+(37)x+(252)
.Which of the following is the correct answer?

−28
and

−9

−56
and

−18

28
and

−9

−28
and

9

Answer 1

help

Answer 2

Sorry I have to organize this for my own thoughts:
\[f(x)=1x^2+37x+252\]
A.)
\[(-28,-9)\]
B.)
\[(-56,-18)\]
C.)
\[(28,-9)\]
D.)
\[(-28,9)\]
Can you Eliminate any of them?

Answer 3

sure

Answer 4

Which one can you eliminate?

Answer 5

d and a

Answer 6

for you that is but for me its all together

Answer 7

Why can you eliminate those?

Answer 8

What makes those choices incorrect?

Answer 9

idk okay i dont know ansers this is colog levol man i didint sine up for this

Answer 10

There are many grammatical errors in that statement you just made, this is simple Algebra I.

Answer 11

So, let's work this out-

Answer 12

here we go again
we're given this: \( 0=1x^2+37x+252 \)
i dont want to take too much space with the quadratic formula, so i will do it by factoring.
lets find a pair of integers whose sum is 37, and and a product of 252.
it takes you some time, to find the 2 numbers -- can you?

Answer 13

The user is currently offline.

Answer 14

thats great -- it means that i can solve it all in one go

so those 2 numbers are \( 9\) AND \(28\) -- i did test it, but lets test it just so whoever is reading this is sure:
\[ 9+28=37 \ \ \ \ \ and \ \ \ \ \ \ \ 9 \times 28=252 \]
that said, the factored terms would be:
\[ (x+9)(x+28)=0 \Rightarrow x+9=0 \\ x+28=0 \]
lets solve for both of them invidually:
\[ x+9=0 \Rightarrow x=0-9 \Rightarrow x_1=-9 \]
\[ x+28=0 \Rightarrow x=0-28 \Rightarrow x_2=-28 \]
and that would be the roots of that expression