Question

Please help..ss will be below

Answer 1

@snowflake0531

Answer 2

so i have the answer lolsies, i was just warned about not giving answers directly or i get in trouble. i’ll try tho

Answer 3

First, determine whether or not this is an exponential function
2 ways you can do this:
1st, graph it
2nd, you can see whether or not the y1 multiplies something to y2, y2 multiplies something to y3, etc.

Answer 4

I don't understand

Answer 5

nvmd, just know that it's exponential

Answer 6

ok

Answer 7

Then you can plug in x values and y values into the \[ y=a(b^x) \]
2 coordinates you have are
(1,12) and (2,36)

Can you plug these 2 coordinates into the above equation? You don't have to solve for anything yet, just plug the numbers in as x and y

Answer 8

doing y=mx+b is so much more understandable

Answer 9

It's not a linear equation so you can't use y=mx+b

Answer 10

36 divide by 12 is 3 and then 108 divided by 36 is 3 too so how would I enter it so it's correct?

Answer 11

B is 3, yes

Answer 12

so how would I enter it

Answer 13

So then plug 3 as b into \[y=a(b^x)\\ y=a(3^x)\] Can you enter the coordinates (1,12) 1 as x, 12 as y into that equation to solve for a?

Answer 14

still a little confused

Answer 15

x=1
y=12
substitute those numbers into \[y=a(3^x)\]

Answer 16

what is a?

Answer 17

that's for you to figure out!!!!!!!!!!!!!!!!!!!!!!! 3qzdfm4qrufhdijcnk4

do you know how to substitute variables?

Answer 18

no bruh

Answer 19

-.-
if x=10 ; b=20
in 2x + 3y, you would do 2(10) + 3(20)
Do you see how I substituted those variables in?

Answer 20

So anyways you would do \[12 = a(3^1) \\ 12 = 3a \\a=4\]

Answer 21

So a = 4 ; b = 3
\[y=a(b^x)\] i hope you have your answer now .-.