Question

i am confused on this one tooo

Answer 1

@AZ please help

Answer 2

@AZ

Answer 3

@AZ or @supie please help

Answer 4

@joe348

Answer 5

ok so do you have any sort of guess of what it could be?

Answer 6

umm not really but it gives me an example wanna see it?

Answer 7

yes please

Answer 8

391

Answer 9

for part A,

they want to know how many times we draw a 1, 2, or 3 card with a Heads

that means look for 1H, 2H, and 3H

those are three outcomes

Answer 10

how many total outcomes are there?

1H
2H
3H
4H
1T
2T
3T
4T

how many do you count?

Answer 11

count each row

1) 1H
2) 2H
3) 3H
4) 4H
5) 1T
6) 2T
7) 3T
8) 4T

how many do you count? I even added numbers by the side

Answer 12

so the answer to the first part, part A is going to be

theoretical probability = favorable outcomes / total outcomes

we said the favorable outcomes is 3
it's 3 because we want 1H, 2H, and 3H

and so how many do you count for the total outcomes?

that's going to be the denominator of the probability

you then have to divide the fraction and round to the hundredths

Answer 13

for part B

and add the numbers underneath the 1H, 2H and 3H in the table

so 132 + 126 + 133 = ??

and so that's your numerator

experimental probability = number of time it occurs / total attempts

and so the number of times it occurs is 132 + 126 + 133

the total number of times is 1050
because that's how many times they tried
(it gives that to you in the question but you can also find it if you add all the numbers in the box)