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A random sample of 130 students is chosen from a population of 4,500 students. If the mean IQ in the sample is 120 with a standard deviation of 5, what is the 99% confidence interval for the students' mean IQ score?
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Answer choices are 118.87–121.13 107.12–132.88 125–135 115–125
@AZ
\( \large CI = \bar{x} \pm z \frac{s}{\sqrt{n}} \) \(\bar{x}\) is your mean which is 120 z is the z-value and for a 99% confidence interval, the value would be 2.58 http://www.ltcconline.net/greenl/courses/201/Estimation/smallConfLevelTable.htm and 's' is the standard deviation of 5 n is how many samples you have which is 130
so can you calculate the 99% confidence interval now?
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