The perimeter of Dana's rectangular garden is 61 feet. The length of her garden is 5 feet more than twice the width. The perimeter of a rectangle can be found by adding the lengths of its four sides.

Question

The perimeter of Dana's rectangular garden is 61 feet.  The length of her garden is 5 feet more than twice the width. The perimeter of a rectangle can be found by adding the lengths of its four sides.

mhanifa · Answer

Do you know perimeter formula?

Extrinix · Answer

Ok so to start off, let's plug in all of the numbers:
$61=(2(w)+5)+(2(w)+5)+w+w$

We need to simplify it:
$61=6w+10$
Then solve for the width (w):
$61=6w+10$      subtract 10 from both sides
$51=6w$      divide by 6 on both sides 
$8.5=w$

Now we need to plug it in:
$61=(2(8.5)+5)+(2(8.5)+5)+8.5+8.5$

Which we can simplify it into:
$P=2l+2w$
$61=2(22)+2(8.5)$

So, from this we can get our length and width:
$l = 22$
$w = 8.5$

noobgamer · Answer

thank you!

mhanifa · Answer

P = 2(w + l)
l = 2w + 5

61 = 2(w + 2w + 5)

Solve for w:

61 = 2(3w + 5)
3w + 5 = 30.5
3w = 25.5
w = 8.5 feet

Find l:

l = 2w + 5 
l = 2(8.5) + 5
l = 22 feet

mhanifa · Answer

@extrinix wrote:

Ok so to start off, let's plug in all of the numbers: $61=(2(w)+5)+(2(w)+5)+w+w$ We need to simplify it: $61=6w+10$ Then solve for the width (w): $61=6w+10$ subtract 10 from both sides $51=6w$ divide by 6 on both sides $8.5=w$ Now we need to plug it in: $61=(2(8.5)+5)+(2(8.5)+5)+8.5+8.5$ Which we can simplify it into: $P=2l+2w$ $61=2(22)+2(8.5)$ So, from this we can get our length and width: $l = 22$ $w = 8.5$

Sorry, didn't see your answer

Extrinix · Answer

It's alright.