The Oddville Academy offers three languages: Oriya, Dakhini, and Dutch (how odd!). Each student takes an odd number of languages – that is, every student takes either one language or three languages. Let $x$ be the number of students taking Oriya, y be the number of students taking Dakhini, z be the number of students taking Dutch, and $t$ be the number of students taking all three languages. Find an expression in terms of x, y, z, and t for the total number of students at the Oddville Academy.
|dw:1623451293717:dw| you can see that each x, y, and z include t in them -- the number who picked one language is going to be: \( x +y+z \ - \ 3t +t \) you can simplify that if you want to
ah ok thank you!
ah i just noticed -- i mean the number of the whole students would be that equation the number of students who only picked one is respectively \( x/y/z-t \) and that is how you get the triple \(t\), plus you should add a \(t\) as well as a normal variable just as excess and yeah thats it
yea thats what i got as well thank you so much for helping :)
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