Which equation represents y = x2 + 12x + 27 in vertex form? y = (x + 6)2 − 9 y = (x + 6)2 + 21 y = (x + 6)2 + 9 y = (x + 6)2 + 27
Do you know how to complete a square?
I've heard of it, never used it in practice
There are two ways: 1. Complete a square 2. Open parenthesis, simplify and compare
Can you do that?
i can try, let me do that
How are you, need help?
ok would it be the last option because the product of the roots (-9,-3?) is 27?
Apply (a + b)^2 = a^2 + 2ab + b^2 to (x + 6)^2 What you get?
Replace a with x and b with 6. What is (x + 6)^2 = ...
(x + 6)^2= x^2 + 2x6 + 6^2 how would i do the 2x6 part?
2 times 6 is ... and 6 times 6 is ...
12 and 36.. i still don't understand where this is all going..?
(x + 6)^2= x^2 + 12x + 36 Now subtract 9 for the first option, what you get?
how did we get to subtracting 9? and subtract it from which number(s)
y = (x + 6)^2 − 9 opened the parenthesis and got: y = x^2 + 12x + 36 - 9 Can you simplify?
x^2+12x+27
Now you need to compare this with the given, are they same or different?
different..
They are same and this option is your answer ... (x^2 and x2 is same in terms of your question)
ok ok so it would be the first option right? that is the on that is showing the same thing that we just did
thank you so much!
No problem
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