Convert 11.42424242 … to a rational expression in the form of a over b, where b ≠ 0. i dont know how to convert 11.42424242 to a rational expression
What they are asking you to do is find the division problem that created this decimal.
no there asking to convert it into the form a over b
A over b is a division problem. :)
oh yh
The way to do this is to remove the repeating section.
how do you do that exactly?
This is done by setting the original number equal to x. In this case, x= 11.4242.... then multiply each side by 100 to get 100x=1142.4242. Then subtract x from each side. (x=11.4242). This will give you 99x=1130.9998. Divide each side by 99 to get x=1130.9998/99. Then simplify this to get the final fraction.
i am not following that solution one thing to notice is that in \( 11.4242... \) , the \( .42 \) is periodic, which the whole thing you write as \( 11.\overset{—}{42} \) -- normally, if 42 was a natural number as a fraction you would write it \( \frac{42}{100} \) right? BUT since its periodic, you should always write it over \( n-1 \) so in our case \( 100-1 \) thus, your answer would be \(11\frac{42}{99} \overset{\text{example: }\: 1\frac{2}{3}=\frac{1\cdot \:3+2}{3}}{\ \ \ \ =========\Rightarrow \ \ \ } \frac{1131}{99} \) can we simplify that?
Your answer seems interesting. It does seem easier to do than the one I provide. However, in the end, they are almost the same with less than a 0.1 difference.
x=11.424242... x=11+0.424242... x=11+0.42+.0042+.000042+... x=11+y y=0.42+.0042+.000042+... it is a geometric seris a1=0.42 \[r=\frac{ 0.0042 }{ 0.42 }=\frac{ 0.0042 }{ 0.4200 }=\frac{ 1 }{ 100 }<1\] \[y=\frac{ a }{1-r }=\frac{ 0.42 }{ 1-0.01 }=\frac{ 0.42 }{ 0.99}=\frac{ 42 }{ 99 }=\frac{ 14 }{ 33 }\] \[x=11+\frac{ 14 }{ 33 }=\frac{ 363+14 }{ 33 }=\frac{ 377 }{ 33 }\]
second method let x=11.424242...(1) 10x=114.24242... 100 x=1142.424242... (2) (2)-(1) gives 99x=1131 \[x=\frac{ 1131 }{ 99 }=\frac{ 377 }{ 33 }\]
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