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jhonyy9:

- this maybe a good way to calcule the ,, ln i " ? so given the Euler's formula of e^ipi = -1 we know that -1 = i^2 so using this we can write e^ipi = i^2 make square root on both sides and get e^(ipi/2) = i^(2/2) e^(ipi/2) = i make logarithm natural on both sides and get ln e^(ipi/2) = ln i (ipi/2)ln e = ln i but we know that ln e = 1 so in this way we get ln i = ipi/2 opinion please - tysm.

XxXNessalulbaddieXxX:

sheeeeeeeeeeeesh u did very wellllll , great way to caculate it

HighIQReptilian:

Real quick, is ipi supposed to be the imaginary i times pi?

Timmyspu:

That is a very good way to calculate that. Good job jhoneyy9

jhonyy9:

@timmyspu wrote:
That is a very good way to calculate that. Good job jhoneyy9
jhoneyy9 correct is jhonyy9 lol tysm

Ashtiel:

my brains hurts because of that

Ashtiel:

Great job, you did amazing

J4ke:

Well done I wish we have the Equation option when we create New Posts.

Jayidc:

You did good

officialJunior:

Next college professor

200082741:

Awesome

LoverGIRL1:

here n late

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