- this maybe a good way to calcule the ,, ln i " ?
so given the Euler's formula of
e^ipi = -1
we know that -1 = i^2 so using this we can write
e^ipi = i^2 make square root on both sides and get
e^(ipi/2) = i^(2/2)
e^(ipi/2) = i make logarithm natural on both sides and get
ln e^(ipi/2) = ln i
(ipi/2)ln e = ln i
but we know that ln e = 1 so in this way we get
ln i = ipi/2
opinion please - tysm.
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XxXNessalulbaddieXxX:
sheeeeeeeeeeeesh u did very wellllll , great way to caculate it
HighIQReptilian:
Real quick, is ipi supposed to be the imaginary i times pi?
Timmyspu:
That is a very good way to calculate that. Good job jhoneyy9
jhonyy9:
@timmyspu wrote:
That is a very good way to calculate that. Good job jhoneyy9
jhoneyy9 correct is jhonyy9
lol
tysm
Ashtiel:
my brains hurts because of that
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Ashtiel:
Great job, you did amazing
J4ke:
Well done I wish we have the Equation option when we create New Posts.
Jayidc:
You did good
officialJunior:
Next college professor
200082741:
Awesome
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