- this maybe a good way to calcule the ,, ln i " ? so given the Euler's formula of e^ipi = -1 we know that -1 = i^2 so using this we can write e^ipi = i^2 make square root on both sides and get e^(ipi/2) = i^(2/2) e^(ipi/2) = i make logarithm natural on both sides and get ln e^(ipi/2) = ln i (ipi/2)ln e = ln i but we know that ln e = 1 so in this way we get ln i = ipi/2 opinion please - tysm.
sheeeeeeeeeeeesh u did very wellllll , great way to caculate it
Real quick, is ipi supposed to be the imaginary i times pi?
That is a very good way to calculate that. Good job jhoneyy9
my brains hurts because of that
Great job, you did amazing
Well done I wish we have the Equation option when we create New Posts.
You did good
Next college professor
Awesome
here n late
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