Help please more math :(
:https://snipboard.io/UYsmTy.jpg

Question

Help please more math :(   
:https://snipboard.io/UYsmTy.jpg

SmokeyBrown · Answer

$$\sqrt{x} * \sqrt[4]{x}$$
Is the same as
$$x ^{1/2} * x ^{1/4}$$
Which would be equal to
$$x ^{(1/2 + 1/4)}$$

kekeman · Answer

So the first one does not have any index or exponent so do i just make my own?

SmokeyBrown · Answer

@kekeman wrote:

So the first one does not have any index or exponent so do i just make my own?

The radical symbol without any number indicates "square root" by default, which is why it is x^1/2 $$\sqrt{x} == x ^{1/2}$$

kekeman · Answer

So the final answer would be x^6/8

kekeman · Answer

@kekeman wrote:

So the final answer would be x^6/8

I mean if we get it into simplest form it would be x^3/4?

SmokeyBrown · Answer

@kekeman wrote:

So the final answer would be x^6/8

I mean if we get it into simplest form it would be x^3/4?

Yup, exactly! Good work, looks like you got it

kekeman · Answer

Ok thank you so much for the help

kekeman · Answer

Well idk why some people are saying to just multiply radicals like normal number to get (4x)

SmokeyBrown · Answer

@kekeman wrote:

Well idk why some people are saying to just multiply radicals like normal number to get (4x)

That would be strange. In this case, I don't think that would apply. The only time you would multiply radicals is if a term with an exponent is taken to another exponent. For instance, (x^a)^b would be the same as x^(a*b) But, again, that does not apply in this case

kekeman · Answer

Ok thanks again

SmokeyBrown · Answer

No problem :)