Question

pre calculus

Answer 1

Negative 4 minus Positive 1. What do you think that is?

Answer 2

Whats 4+1?

Answer 3

-5

Answer 4

Yes correct.

Answer 5

If you ever need help I love intergers.

Answer 6

You could also use a number line those are a helpful strategy too.

Answer 7

So you have (-4,-1) as your center
it's tangent to the y axis
which means it touches the y axis

So from x equals -4 you have to add for to make is x equals 0
so the distance from the coordinate (-4,-1) to the y axis is 4
which makes the radius 4

And if you remember the equation for a circle, it is \((x-h)^2 + (y-k)^2 = r^2\)
where (h,k) is the coordinate, (-4,-1) and the radius is 4

Answer 8

Are you saying the answers 4?

Answer 9

so what do I do?

Answer 10

IS this NOT intergers?

Answer 11

(x-4)^2+(y-1)^2=4^2

Answer 12

actually it would be \((x-(-4)^2 + (y-1)^2 = 4^2\)

try again

Answer 13

thats the answer?

Answer 14

or do we multiply the 4

Answer 15

**(y-(-1)


simplify it

Answer 16

what is -(-) ?

Answer 17

it makes a positive

Answer 18

so \((x-(-4)^2 + (x-(-1)^2 = 4^2\) simplified is..?

Answer 19

(x+y-17)=16

Answer 20

how'd you get that...

Answer 21

you still want it to be in the form of \((x-h)^2 + (y-k)^2 = r^2\) form

Answer 22

but there isnt another paranthesis for the x

Answer 23

oh oops *** \((x-(-4))^2 + (y-(-1))^2 = 4^2\)

Answer 24

y=-x^2-8x+1

Answer 25

no, keep it in this form

Answer 26

sorry im not sure

Answer 27

wait

Answer 28

i found it out

Answer 29

(x+4)^2+(y+1)^2=16

Answer 30

yes good job

Answer 31

although i'm not sure whether it'd want 4^2 or 16

Answer 32

let me see

Answer 33

Probably 4^2 tho

Answer 34

16 was right

Answer 35

alright, nice