x/2x+8=3/x+2...SOLVE FOR X
\[\frac{ x }{ 2x + 8 } = \frac{ 3 }{ x + 2 }\]
The fractions make this a bit awkward to solve, so what do you think would be your first step?
Well you could start by removing the denominators so that you don't have to divide.
Cross multiplication is a pretty simple way to do this. Basically do:\[x \times (x + 2) = ?\] and \[3 \times (2x + 8)\]
@bracefacejah Does that make sense from there?
yes thnks
do i add after that?
After this you should get: \[x^2 + 2x = 6x + 24\]
Looking at this you know you're going to have to use the quadratic formula to solve for this, because of the x^2, so basically you want to create ax + by + c = 0, so get all the terms to the left side.
Subtract 6x from both sides, then 24 from both sides, you get \[x^2 - 4x - 24 = 0\]
If you don't know the quadratic formula, this is it: \[x = \frac{ -b \pm \sqrt (b^2 - 4ac) }{ 2a }\] Where a quadratic equation looks like, ax^2 + by + c = 0 So from x^2 - 4x - 24 we can grab the coefficients, a = 1, b = -4 c = -24 Then you just input these into the formula and solve for x.
Does that make sense so far?
yes
\[x = \frac{ -(-4) \pm \sqrt(-4)^2 - 4(1)(-24) }{ 2(1) }\]
i got my answer... -5
Are you sure?
yes
You can get very different answers based off of how you look at the fractions.
i checked my answer and its right
Like is it (x/2x) +8=(3/x)+2 or x/2x+8=3/x+2
no it was -5
Frankly, I don't see how you get 5 from this. I double checked it with Wolfram. Are you sure you gave me the right problem lol?
yes i gave the right question and I put it into the system I'm getting questions on and it says its right
Oh okay. It may just be a lesson glitch or something. If you input x/(2x+8)=3/(x+2) into Wolfram, you definitely don't get -5
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