Question

The total mechanical energy of an object with mass m at height h in a closed system can be written as ME=1/2mv^2+mgh. Solve for v, the velocity of the object, in terms of the given quantities.

Answer 1

@vocaloid

Answer 2

subtract mgh from both sides

from there, you'll have (1/2)mv^2 on the right side

divide both sides by (1/2)m and take the square root

Answer 3

i'm sorry , i'm having difficulty in doing it

Answer 4

ME = (1/2)mv^2 + mgh

subtracting mgh from both sides:

ME - mgh = (1/2)mv^2

divide both sides by (1/2)m

2(ME - mgh)/m = v^2

take the square root of both sides

v = sqrt[2(ME - mgh)/m]